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Method added to Object.prototype repeats infinite times
Adding a Method to an Existing Object InstanceWhat's the difference between a method and a function?How to measure time taken by a function to executeConvert a Unix timestamp to time in JavaScriptRepeat Character N TimesPass Method as Parameter using C#Programmatically Lighten or Darken a hex color (or rgb, and blend colors)Object.prototype is Verboten?Is it not possible to stringify an Error using JSON.stringify?can't find the method I added to the external javascript library
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I was messing around with the browser console to improve my javascript skills.
When I tried to add a method to Object.prototype, that returns its instance as json, something odd happened:
Right at the end of the method, it jumps back to the for-in loop and execute it again. Over and over again...
It does not return anything and just continues to jump back and repeat.
The code:
Object.prototype.toJSON = function()
var tempObj = ;
for (let key in this)
if (this.hasOwnProperty(key))
let value = this[key];
tempObj[key] = value;
return JSON.stringify(tempObj);
I know you should not add methods to Object.prototype. (If I'm wrong please correct me)
This is for learning purpose only.
Can you please explain to me, why this method behaves like it does?
I don't want to know, how it would work, but why it does not work. :)
Thank you very much!
javascript methods prototype for-in-loop
asked Mar 8 at 6:13
TechnikhighkneeTechnikhighknee
132
add a comment |
I was messing around with the browser console to improve my javascript skills.
When I tried to add a method to Object.prototype, that returns its instance as json, something odd happened:
Right at the end of the method, it jumps back to the for-in loop and execute it again. Over and over again...
It does not return anything and just continues to jump back and repeat.
The code:
Object.prototype.toJSON = function()
var tempObj = ;
for (let key in this)
if (this.hasOwnProperty(key))
let value = this[key];
tempObj[key] = value;
return JSON.stringify(tempObj);
I know you should not add methods to Object.prototype. (If I'm wrong please correct me)
This is for learning purpose only.
Can you please explain to me, why this method behaves like it does?
I don't want to know, how it would work, but why it does not work. :)
Thank you very much!
javascript methods prototype for-in-loop
asked Mar 8 at 6:13
TechnikhighkneeTechnikhighknee
132
4
JSON.stringifycallstoJSONif it exists on an object (which now exists on EVERY object), and you've madetoJSONcallJSON.stringify... the recursion is obvious
– Jaromanda X
Mar 8 at 6:19
@JaromandaX that explains everything.. lmao Thanks alot!
– Technikhighknee
Mar 8 at 6:21
2
by the way, you can make it "work" byvar tempObj = Object.create(null);- thentempObjis not anObject:p
– Jaromanda X
Mar 8 at 6:23
Good to know! Thanks a lot!
– Technikhighknee
Mar 8 at 6:33
add a comment |
I was messing around with the browser console to improve my javascript skills.
When I tried to add a method to Object.prototype, that returns its instance as json, something odd happened:
Right at the end of the method, it jumps back to the for-in loop and execute it again. Over and over again...
It does not return anything and just continues to jump back and repeat.
The code:
Object.prototype.toJSON = function()
var tempObj = ;
for (let key in this)
if (this.hasOwnProperty(key))
let value = this[key];
tempObj[key] = value;
return JSON.stringify(tempObj);
I know you should not add methods to Object.prototype. (If I'm wrong please correct me)
This is for learning purpose only.
Can you please explain to me, why this method behaves like it does?
I don't want to know, how it would work, but why it does not work. :)
Thank you very much!
javascript methods prototype for-in-loop
asked Mar 8 at 6:13
TechnikhighkneeTechnikhighknee
132
I was messing around with the browser console to improve my javascript skills.
When I tried to add a method to Object.prototype, that returns its instance as json, something odd happened:
Right at the end of the method, it jumps back to the for-in loop and execute it again. Over and over again...
It does not return anything and just continues to jump back and repeat.
The code:
Object.prototype.toJSON = function()
var tempObj = ;
for (let key in this)
if (this.hasOwnProperty(key))
let value = this[key];
tempObj[key] = value;
return JSON.stringify(tempObj);
I know you should not add methods to Object.prototype. (If I'm wrong please correct me)
This is for learning purpose only.
Can you please explain to me, why this method behaves like it does?
I don't want to know, how it would work, but why it does not work. :)
Thank you very much!
javascript methods prototype for-in-loop
javascript methods prototype for-in-loop
asked Mar 8 at 6:13
TechnikhighkneeTechnikhighknee
132
asked Mar 8 at 6:13
TechnikhighkneeTechnikhighknee
132
asked Mar 8 at 6:13
TechnikhighkneeTechnikhighknee
132
asked Mar 8 at 6:13
TechnikhighkneeTechnikhighknee
132
asked Mar 8 at 6:13
TechnikhighkneeTechnikhighknee
132
132
4
JSON.stringifycallstoJSONif it exists on an object (which now exists on EVERY object), and you've madetoJSONcallJSON.stringify... the recursion is obvious
– Jaromanda X
Mar 8 at 6:19
@JaromandaX that explains everything.. lmao Thanks alot!
– Technikhighknee
Mar 8 at 6:21
2
by the way, you can make it "work" byvar tempObj = Object.create(null);- thentempObjis not anObject:p
– Jaromanda X
Mar 8 at 6:23
Good to know! Thanks a lot!
– Technikhighknee
Mar 8 at 6:33
add a comment |
4
JSON.stringifycallstoJSONif it exists on an object (which now exists on EVERY object), and you've madetoJSONcallJSON.stringify... the recursion is obvious
– Jaromanda X
Mar 8 at 6:19
@JaromandaX that explains everything.. lmao Thanks alot!
– Technikhighknee
Mar 8 at 6:21
2
by the way, you can make it "work" byvar tempObj = Object.create(null);- thentempObjis not anObject:p
– Jaromanda X
Mar 8 at 6:23
Good to know! Thanks a lot!
– Technikhighknee
Mar 8 at 6:33
4
4
JSON.stringify calls toJSON if it exists on an object (which now exists on EVERY object), and you've made toJSON call JSON.stringify ... the recursion is obvious– Jaromanda X
Mar 8 at 6:19
JSON.stringify calls toJSON if it exists on an object (which now exists on EVERY object), and you've made toJSON call JSON.stringify ... the recursion is obvious– Jaromanda X
Mar 8 at 6:19
@JaromandaX that explains everything.. lmao Thanks alot!
– Technikhighknee
Mar 8 at 6:21
@JaromandaX that explains everything.. lmao Thanks alot!
– Technikhighknee
Mar 8 at 6:21
2
2
by the way, you can make it "work" by
var tempObj = Object.create(null); - then tempObj is not an Object :p– Jaromanda X
Mar 8 at 6:23
by the way, you can make it "work" by
var tempObj = Object.create(null); - then tempObj is not an Object :p– Jaromanda X
Mar 8 at 6:23
Good to know! Thanks a lot!
– Technikhighknee
Mar 8 at 6:33
Good to know! Thanks a lot!
– Technikhighknee
Mar 8 at 6:33
add a comment |
1 Answer
1
active
oldest
votes
Because JSON.stringify() whill check if the object have a method toJSON, it will call toJSON if there have one.
You replace the origin toJSON to yours, and in your toJSON called JSON.stringify(), so there create a call loop.
check this:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify#Description
answered Mar 8 at 6:27
Li JinyaoLi Jinyao
169315
add a comment |
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1 Answer
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votes
Because JSON.stringify() whill check if the object have a method toJSON, it will call toJSON if there have one.
You replace the origin toJSON to yours, and in your toJSON called JSON.stringify(), so there create a call loop.
check this:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify#Description
answered Mar 8 at 6:27
Li JinyaoLi Jinyao
169315
add a comment |
Because JSON.stringify() whill check if the object have a method toJSON, it will call toJSON if there have one.
You replace the origin toJSON to yours, and in your toJSON called JSON.stringify(), so there create a call loop.
check this:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify#Description
answered Mar 8 at 6:27
Li JinyaoLi Jinyao
169315
add a comment |
Because JSON.stringify() whill check if the object have a method toJSON, it will call toJSON if there have one.
You replace the origin toJSON to yours, and in your toJSON called JSON.stringify(), so there create a call loop.
check this:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify#Description
answered Mar 8 at 6:27
Li JinyaoLi Jinyao
169315
Because JSON.stringify() whill check if the object have a method toJSON, it will call toJSON if there have one.
You replace the origin toJSON to yours, and in your toJSON called JSON.stringify(), so there create a call loop.
check this:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify#Description
answered Mar 8 at 6:27
Li JinyaoLi Jinyao
169315
answered Mar 8 at 6:27
Li JinyaoLi Jinyao
169315
answered Mar 8 at 6:27
Li JinyaoLi Jinyao
169315
answered Mar 8 at 6:27
Li JinyaoLi Jinyao
169315
169315
add a comment |
add a comment |
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4
JSON.stringifycallstoJSONif it exists on an object (which now exists on EVERY object), and you've madetoJSONcallJSON.stringify... the recursion is obvious– Jaromanda X
Mar 8 at 6:19
@JaromandaX that explains everything.. lmao Thanks alot!
– Technikhighknee
Mar 8 at 6:21
2
by the way, you can make it "work" by
var tempObj = Object.create(null);- thentempObjis not anObject:p– Jaromanda X
Mar 8 at 6:23
Good to know! Thanks a lot!
– Technikhighknee
Mar 8 at 6:33