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MYSQL Cumulative Totals with SUM and Subquery



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!Can I concatenate multiple MySQL rows into one field?Should I use the datetime or timestamp data type in MySQL?How to get a list of MySQL user accountsMySql conditional order byInsert into a MySQL table or update if existsHow to reset AUTO_INCREMENT in MySQL?MySQL INNER JOIN of 3 tables with count and totalsHow to import an SQL file using the command line in MySQL?SQL Query with 3 Tables using SUM not workingSQL query calculate and display sum data per each month of the year



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0















I have the below table:



CREATE TABLE `_loans` (
`loan_id` int(11) NOT NULL,
`price` float(7,2) NOT NULL,
`term` int(11) NOT NULL,
`app_date` date NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

INSERT INTO `_loans` (`loan_id`, `price`, `term`, `app_date`) VALUES
(1, 299.00, 24, '2019-01-23'),
(2, 774.00, 24, '2019-01-24'),
(3, 817.80, 24, '2019-01-24'),
(4, 279.99, 24, '2019-01-28'),
(5, 463.99, 24, '2019-01-28'),
(6, 0.00, 24, '2019-01-28'),
(7, 357.00, 24, '2019-02-02'),
(8, 386.98, 24, '2019-02-04'),
(9, 846.00, 24, '2019-02-04'),
(10, 713.99, 24, '2019-02-06'),
(11, 0.00, 24, '2019-02-07'),
(12, 579.00, 24, '2019-02-11'),
(13, 179.00, 24, '2019-02-13'),
(14, 0.00, 24, '2019-02-19'),
(15, 259.00, 24, '2019-02-21'),
(16, 249.99, 24, '2019-02-26'),
(17, 319.00, 24, '2019-03-02'),
(18, 1108.99, 24, '2019-03-05'),
(19, 319.00, 24, '2019-03-05'),
(20, 199.97, 24, '2019-03-06');

ALTER TABLE `_loans`
ADD PRIMARY KEY (`loan_id`),
ADD KEY `app_date` (`app_date`);


And the below query, which gives a monthly summary of the table data:



SELECT 
MONTHNAME(w.app_date) month,
YEAR(w.app_date) year,
COUNT(*) contracts,
SUM(w.total_price) totals,
@running_total := @running_total + SUM(w.total_price) running_totals
FROM (
SELECT
app_date,
SUM(price * term) total_price
FROM _loans l
GROUP BY l.loan_id
) w
JOIN (SELECT @running_total := 0) r
GROUP BY YEAR(w.app_date), MONTH(w.app_date)
ORDER BY YEAR(w.app_date), MONTH(w.app_date) ASC


I need a running total of the values from the 'totals' column. Everything works well except the cumulative total, which is not accumulating.



month | year | contracts | totals | running_totals 
------------------------------------------------------------------
January | 2019 | 6 | 63234.72 | 63234.71923828125
February | 2019 | 10 | 85703.04 | 85703.04016113281
March | 2019 | 4 | 46727.04 | 46727.039794921875









share|improve this question






















  • Note that price is often DECIMAL

    – Strawberry
    Mar 9 at 9:35

















0















I have the below table:



CREATE TABLE `_loans` (
`loan_id` int(11) NOT NULL,
`price` float(7,2) NOT NULL,
`term` int(11) NOT NULL,
`app_date` date NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

INSERT INTO `_loans` (`loan_id`, `price`, `term`, `app_date`) VALUES
(1, 299.00, 24, '2019-01-23'),
(2, 774.00, 24, '2019-01-24'),
(3, 817.80, 24, '2019-01-24'),
(4, 279.99, 24, '2019-01-28'),
(5, 463.99, 24, '2019-01-28'),
(6, 0.00, 24, '2019-01-28'),
(7, 357.00, 24, '2019-02-02'),
(8, 386.98, 24, '2019-02-04'),
(9, 846.00, 24, '2019-02-04'),
(10, 713.99, 24, '2019-02-06'),
(11, 0.00, 24, '2019-02-07'),
(12, 579.00, 24, '2019-02-11'),
(13, 179.00, 24, '2019-02-13'),
(14, 0.00, 24, '2019-02-19'),
(15, 259.00, 24, '2019-02-21'),
(16, 249.99, 24, '2019-02-26'),
(17, 319.00, 24, '2019-03-02'),
(18, 1108.99, 24, '2019-03-05'),
(19, 319.00, 24, '2019-03-05'),
(20, 199.97, 24, '2019-03-06');

ALTER TABLE `_loans`
ADD PRIMARY KEY (`loan_id`),
ADD KEY `app_date` (`app_date`);


And the below query, which gives a monthly summary of the table data:



SELECT 
MONTHNAME(w.app_date) month,
YEAR(w.app_date) year,
COUNT(*) contracts,
SUM(w.total_price) totals,
@running_total := @running_total + SUM(w.total_price) running_totals
FROM (
SELECT
app_date,
SUM(price * term) total_price
FROM _loans l
GROUP BY l.loan_id
) w
JOIN (SELECT @running_total := 0) r
GROUP BY YEAR(w.app_date), MONTH(w.app_date)
ORDER BY YEAR(w.app_date), MONTH(w.app_date) ASC


I need a running total of the values from the 'totals' column. Everything works well except the cumulative total, which is not accumulating.



month | year | contracts | totals | running_totals 
------------------------------------------------------------------
January | 2019 | 6 | 63234.72 | 63234.71923828125
February | 2019 | 10 | 85703.04 | 85703.04016113281
March | 2019 | 4 | 46727.04 | 46727.039794921875









share|improve this question






















  • Note that price is often DECIMAL

    – Strawberry
    Mar 9 at 9:35













0












0








0








I have the below table:



CREATE TABLE `_loans` (
`loan_id` int(11) NOT NULL,
`price` float(7,2) NOT NULL,
`term` int(11) NOT NULL,
`app_date` date NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

INSERT INTO `_loans` (`loan_id`, `price`, `term`, `app_date`) VALUES
(1, 299.00, 24, '2019-01-23'),
(2, 774.00, 24, '2019-01-24'),
(3, 817.80, 24, '2019-01-24'),
(4, 279.99, 24, '2019-01-28'),
(5, 463.99, 24, '2019-01-28'),
(6, 0.00, 24, '2019-01-28'),
(7, 357.00, 24, '2019-02-02'),
(8, 386.98, 24, '2019-02-04'),
(9, 846.00, 24, '2019-02-04'),
(10, 713.99, 24, '2019-02-06'),
(11, 0.00, 24, '2019-02-07'),
(12, 579.00, 24, '2019-02-11'),
(13, 179.00, 24, '2019-02-13'),
(14, 0.00, 24, '2019-02-19'),
(15, 259.00, 24, '2019-02-21'),
(16, 249.99, 24, '2019-02-26'),
(17, 319.00, 24, '2019-03-02'),
(18, 1108.99, 24, '2019-03-05'),
(19, 319.00, 24, '2019-03-05'),
(20, 199.97, 24, '2019-03-06');

ALTER TABLE `_loans`
ADD PRIMARY KEY (`loan_id`),
ADD KEY `app_date` (`app_date`);


And the below query, which gives a monthly summary of the table data:



SELECT 
MONTHNAME(w.app_date) month,
YEAR(w.app_date) year,
COUNT(*) contracts,
SUM(w.total_price) totals,
@running_total := @running_total + SUM(w.total_price) running_totals
FROM (
SELECT
app_date,
SUM(price * term) total_price
FROM _loans l
GROUP BY l.loan_id
) w
JOIN (SELECT @running_total := 0) r
GROUP BY YEAR(w.app_date), MONTH(w.app_date)
ORDER BY YEAR(w.app_date), MONTH(w.app_date) ASC


I need a running total of the values from the 'totals' column. Everything works well except the cumulative total, which is not accumulating.



month | year | contracts | totals | running_totals 
------------------------------------------------------------------
January | 2019 | 6 | 63234.72 | 63234.71923828125
February | 2019 | 10 | 85703.04 | 85703.04016113281
March | 2019 | 4 | 46727.04 | 46727.039794921875









share|improve this question














I have the below table:



CREATE TABLE `_loans` (
`loan_id` int(11) NOT NULL,
`price` float(7,2) NOT NULL,
`term` int(11) NOT NULL,
`app_date` date NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

INSERT INTO `_loans` (`loan_id`, `price`, `term`, `app_date`) VALUES
(1, 299.00, 24, '2019-01-23'),
(2, 774.00, 24, '2019-01-24'),
(3, 817.80, 24, '2019-01-24'),
(4, 279.99, 24, '2019-01-28'),
(5, 463.99, 24, '2019-01-28'),
(6, 0.00, 24, '2019-01-28'),
(7, 357.00, 24, '2019-02-02'),
(8, 386.98, 24, '2019-02-04'),
(9, 846.00, 24, '2019-02-04'),
(10, 713.99, 24, '2019-02-06'),
(11, 0.00, 24, '2019-02-07'),
(12, 579.00, 24, '2019-02-11'),
(13, 179.00, 24, '2019-02-13'),
(14, 0.00, 24, '2019-02-19'),
(15, 259.00, 24, '2019-02-21'),
(16, 249.99, 24, '2019-02-26'),
(17, 319.00, 24, '2019-03-02'),
(18, 1108.99, 24, '2019-03-05'),
(19, 319.00, 24, '2019-03-05'),
(20, 199.97, 24, '2019-03-06');

ALTER TABLE `_loans`
ADD PRIMARY KEY (`loan_id`),
ADD KEY `app_date` (`app_date`);


And the below query, which gives a monthly summary of the table data:



SELECT 
MONTHNAME(w.app_date) month,
YEAR(w.app_date) year,
COUNT(*) contracts,
SUM(w.total_price) totals,
@running_total := @running_total + SUM(w.total_price) running_totals
FROM (
SELECT
app_date,
SUM(price * term) total_price
FROM _loans l
GROUP BY l.loan_id
) w
JOIN (SELECT @running_total := 0) r
GROUP BY YEAR(w.app_date), MONTH(w.app_date)
ORDER BY YEAR(w.app_date), MONTH(w.app_date) ASC


I need a running total of the values from the 'totals' column. Everything works well except the cumulative total, which is not accumulating.



month | year | contracts | totals | running_totals 
------------------------------------------------------------------
January | 2019 | 6 | 63234.72 | 63234.71923828125
February | 2019 | 10 | 85703.04 | 85703.04016113281
March | 2019 | 4 | 46727.04 | 46727.039794921875






mysql sql






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 9 at 2:50









ratherBeKitingratherBeKiting

155112




155112












  • Note that price is often DECIMAL

    – Strawberry
    Mar 9 at 9:35

















  • Note that price is often DECIMAL

    – Strawberry
    Mar 9 at 9:35
















Note that price is often DECIMAL

– Strawberry
Mar 9 at 9:35





Note that price is often DECIMAL

– Strawberry
Mar 9 at 9:35












2 Answers
2






active

oldest

votes


















1














This isn't working because of the GROUPing. You need to nest the GROUPing as a subquery and compute the running total from that:



SELECT monthname as month, year, contracts, totals,
@running_total := @running_total + totals AS running_totals
FROM (SELECT
MONTHNAME(w.app_date) monthname,
MONTH(w.app_date) monthnum,
YEAR(w.app_date) year,
COUNT(*) contracts,
SUM(w.total_price) totals
FROM (SELECT
app_date,
SUM(price * term) total_price
FROM _loans l
GROUP BY l.loan_id
) w
GROUP BY year, monthnum, monthname
) t
JOIN (SELECT @running_total := 0) r
ORDER BY year, monthnum ASC


Output:



month year contracts totals running_totals
January 2019 6 63234.72 63234.71923828125
February 2019 10 85703.04 148937.75939941406
March 2019 4 46727.04 195664.79919433594


Demo on dbfiddle






share|improve this answer






























    0














    Your query is overly complicated. The subquery is not necessary for the aggregation. However, it is necessary for the use of variables:



    SELECT month, year, total_price,
    (@running_total := @running_total + total_price) as running_totals
    FROM (SELECT MONTHNAME(l.app_date) as month,
    YEAR(l.app_date) as year,
    MONTH(l.app_date) as mon,
    COUNT(DISTINCT l.loan_id) as contracts,
    SUM(l.price * l.term) total_price
    FROM _loans l
    GROUP BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
    ORDER BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
    ) l CROSS JOIN
    (SELECT @running_total := 0) params
    ORDER BY year, mon ASC





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      This isn't working because of the GROUPing. You need to nest the GROUPing as a subquery and compute the running total from that:



      SELECT monthname as month, year, contracts, totals,
      @running_total := @running_total + totals AS running_totals
      FROM (SELECT
      MONTHNAME(w.app_date) monthname,
      MONTH(w.app_date) monthnum,
      YEAR(w.app_date) year,
      COUNT(*) contracts,
      SUM(w.total_price) totals
      FROM (SELECT
      app_date,
      SUM(price * term) total_price
      FROM _loans l
      GROUP BY l.loan_id
      ) w
      GROUP BY year, monthnum, monthname
      ) t
      JOIN (SELECT @running_total := 0) r
      ORDER BY year, monthnum ASC


      Output:



      month year contracts totals running_totals
      January 2019 6 63234.72 63234.71923828125
      February 2019 10 85703.04 148937.75939941406
      March 2019 4 46727.04 195664.79919433594


      Demo on dbfiddle






      share|improve this answer



























        1














        This isn't working because of the GROUPing. You need to nest the GROUPing as a subquery and compute the running total from that:



        SELECT monthname as month, year, contracts, totals,
        @running_total := @running_total + totals AS running_totals
        FROM (SELECT
        MONTHNAME(w.app_date) monthname,
        MONTH(w.app_date) monthnum,
        YEAR(w.app_date) year,
        COUNT(*) contracts,
        SUM(w.total_price) totals
        FROM (SELECT
        app_date,
        SUM(price * term) total_price
        FROM _loans l
        GROUP BY l.loan_id
        ) w
        GROUP BY year, monthnum, monthname
        ) t
        JOIN (SELECT @running_total := 0) r
        ORDER BY year, monthnum ASC


        Output:



        month year contracts totals running_totals
        January 2019 6 63234.72 63234.71923828125
        February 2019 10 85703.04 148937.75939941406
        March 2019 4 46727.04 195664.79919433594


        Demo on dbfiddle






        share|improve this answer

























          1












          1








          1







          This isn't working because of the GROUPing. You need to nest the GROUPing as a subquery and compute the running total from that:



          SELECT monthname as month, year, contracts, totals,
          @running_total := @running_total + totals AS running_totals
          FROM (SELECT
          MONTHNAME(w.app_date) monthname,
          MONTH(w.app_date) monthnum,
          YEAR(w.app_date) year,
          COUNT(*) contracts,
          SUM(w.total_price) totals
          FROM (SELECT
          app_date,
          SUM(price * term) total_price
          FROM _loans l
          GROUP BY l.loan_id
          ) w
          GROUP BY year, monthnum, monthname
          ) t
          JOIN (SELECT @running_total := 0) r
          ORDER BY year, monthnum ASC


          Output:



          month year contracts totals running_totals
          January 2019 6 63234.72 63234.71923828125
          February 2019 10 85703.04 148937.75939941406
          March 2019 4 46727.04 195664.79919433594


          Demo on dbfiddle






          share|improve this answer













          This isn't working because of the GROUPing. You need to nest the GROUPing as a subquery and compute the running total from that:



          SELECT monthname as month, year, contracts, totals,
          @running_total := @running_total + totals AS running_totals
          FROM (SELECT
          MONTHNAME(w.app_date) monthname,
          MONTH(w.app_date) monthnum,
          YEAR(w.app_date) year,
          COUNT(*) contracts,
          SUM(w.total_price) totals
          FROM (SELECT
          app_date,
          SUM(price * term) total_price
          FROM _loans l
          GROUP BY l.loan_id
          ) w
          GROUP BY year, monthnum, monthname
          ) t
          JOIN (SELECT @running_total := 0) r
          ORDER BY year, monthnum ASC


          Output:



          month year contracts totals running_totals
          January 2019 6 63234.72 63234.71923828125
          February 2019 10 85703.04 148937.75939941406
          March 2019 4 46727.04 195664.79919433594


          Demo on dbfiddle







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 9 at 3:06









          NickNick

          41.7k142444




          41.7k142444























              0














              Your query is overly complicated. The subquery is not necessary for the aggregation. However, it is necessary for the use of variables:



              SELECT month, year, total_price,
              (@running_total := @running_total + total_price) as running_totals
              FROM (SELECT MONTHNAME(l.app_date) as month,
              YEAR(l.app_date) as year,
              MONTH(l.app_date) as mon,
              COUNT(DISTINCT l.loan_id) as contracts,
              SUM(l.price * l.term) total_price
              FROM _loans l
              GROUP BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
              ORDER BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
              ) l CROSS JOIN
              (SELECT @running_total := 0) params
              ORDER BY year, mon ASC





              share|improve this answer



























                0














                Your query is overly complicated. The subquery is not necessary for the aggregation. However, it is necessary for the use of variables:



                SELECT month, year, total_price,
                (@running_total := @running_total + total_price) as running_totals
                FROM (SELECT MONTHNAME(l.app_date) as month,
                YEAR(l.app_date) as year,
                MONTH(l.app_date) as mon,
                COUNT(DISTINCT l.loan_id) as contracts,
                SUM(l.price * l.term) total_price
                FROM _loans l
                GROUP BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
                ORDER BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
                ) l CROSS JOIN
                (SELECT @running_total := 0) params
                ORDER BY year, mon ASC





                share|improve this answer

























                  0












                  0








                  0







                  Your query is overly complicated. The subquery is not necessary for the aggregation. However, it is necessary for the use of variables:



                  SELECT month, year, total_price,
                  (@running_total := @running_total + total_price) as running_totals
                  FROM (SELECT MONTHNAME(l.app_date) as month,
                  YEAR(l.app_date) as year,
                  MONTH(l.app_date) as mon,
                  COUNT(DISTINCT l.loan_id) as contracts,
                  SUM(l.price * l.term) total_price
                  FROM _loans l
                  GROUP BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
                  ORDER BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
                  ) l CROSS JOIN
                  (SELECT @running_total := 0) params
                  ORDER BY year, mon ASC





                  share|improve this answer













                  Your query is overly complicated. The subquery is not necessary for the aggregation. However, it is necessary for the use of variables:



                  SELECT month, year, total_price,
                  (@running_total := @running_total + total_price) as running_totals
                  FROM (SELECT MONTHNAME(l.app_date) as month,
                  YEAR(l.app_date) as year,
                  MONTH(l.app_date) as mon,
                  COUNT(DISTINCT l.loan_id) as contracts,
                  SUM(l.price * l.term) total_price
                  FROM _loans l
                  GROUP BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
                  ORDER BY l.loan_id, YEAR(w.app_date), MONTH(w.app_date)
                  ) l CROSS JOIN
                  (SELECT @running_total := 0) params
                  ORDER BY year, mon ASC






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 9 at 3:56









                  Gordon LinoffGordon Linoff

                  801k37321426




                  801k37321426



























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