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How to use a variable from a different class
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I have a rather simple question. How can I use variables from different classes in dart?
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var useVariable = variable + 1; // This gives me an error saying:
// Undefined name 'variable'
dart
add a comment |
I have a rather simple question. How can I use variables from different classes in dart?
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var useVariable = variable + 1; // This gives me an error saying:
// Undefined name 'variable'
dart
add a comment |
I have a rather simple question. How can I use variables from different classes in dart?
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var useVariable = variable + 1; // This gives me an error saying:
// Undefined name 'variable'
dart
I have a rather simple question. How can I use variables from different classes in dart?
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var useVariable = variable + 1; // This gives me an error saying:
// Undefined name 'variable'
dart
dart
asked Mar 9 at 2:20
ExtraExtra
7811
7811
add a comment |
add a comment |
1 Answer
1
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Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.
Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.
That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:
Option 1 - static member variable
You can make a static (class level) member, which will be the same for all objects.
class ContainsVariable
static var variable = 1;
class DoesNotContainVariable
var useVariable = ContainsVariable.variable + 1; // here, you are using a
// static (class) variable,
// not an instance variable.
// That is why you are using
// the class name.
Option 2 - instantiation
You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var instanceOfContainsVariable;
var useVariable;
DoesNotContainVariable() // this is a constructor function
var instanceOfContainsVariable = new ContainsVariable();
useVariable = instanceOfContainsVariable.variable + 1;
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.
Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.
That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:
Option 1 - static member variable
You can make a static (class level) member, which will be the same for all objects.
class ContainsVariable
static var variable = 1;
class DoesNotContainVariable
var useVariable = ContainsVariable.variable + 1; // here, you are using a
// static (class) variable,
// not an instance variable.
// That is why you are using
// the class name.
Option 2 - instantiation
You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var instanceOfContainsVariable;
var useVariable;
DoesNotContainVariable() // this is a constructor function
var instanceOfContainsVariable = new ContainsVariable();
useVariable = instanceOfContainsVariable.variable + 1;
add a comment |
Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.
Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.
That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:
Option 1 - static member variable
You can make a static (class level) member, which will be the same for all objects.
class ContainsVariable
static var variable = 1;
class DoesNotContainVariable
var useVariable = ContainsVariable.variable + 1; // here, you are using a
// static (class) variable,
// not an instance variable.
// That is why you are using
// the class name.
Option 2 - instantiation
You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var instanceOfContainsVariable;
var useVariable;
DoesNotContainVariable() // this is a constructor function
var instanceOfContainsVariable = new ContainsVariable();
useVariable = instanceOfContainsVariable.variable + 1;
add a comment |
Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.
Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.
That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:
Option 1 - static member variable
You can make a static (class level) member, which will be the same for all objects.
class ContainsVariable
static var variable = 1;
class DoesNotContainVariable
var useVariable = ContainsVariable.variable + 1; // here, you are using a
// static (class) variable,
// not an instance variable.
// That is why you are using
// the class name.
Option 2 - instantiation
You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var instanceOfContainsVariable;
var useVariable;
DoesNotContainVariable() // this is a constructor function
var instanceOfContainsVariable = new ContainsVariable();
useVariable = instanceOfContainsVariable.variable + 1;
Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.
Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.
That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:
Option 1 - static member variable
You can make a static (class level) member, which will be the same for all objects.
class ContainsVariable
static var variable = 1;
class DoesNotContainVariable
var useVariable = ContainsVariable.variable + 1; // here, you are using a
// static (class) variable,
// not an instance variable.
// That is why you are using
// the class name.
Option 2 - instantiation
You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.
class ContainsVariable
var variable = 1;
class DoesNotContainVariable
var instanceOfContainsVariable;
var useVariable;
DoesNotContainVariable() // this is a constructor function
var instanceOfContainsVariable = new ContainsVariable();
useVariable = instanceOfContainsVariable.variable + 1;
answered Mar 9 at 5:35
Balázs PukliBalázs Pukli
1133
1133
add a comment |
add a comment |
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