Multicast between applications on the same host Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Data science time! April 2019 and salary with experience The Ask Question Wizard is Live!Differences between HashMap and Hashtable?What is the difference between public, protected, package-private and private in Java?Finding the multicast IP that a datagram was sent toJava multicast socket not received out of localhostMulticastSocket constructors and binding to port or SocketAddressJava multiple multicast sockets in same group on same host and portReceiving Unicast on Multicast socketJava UDP multicast, determine which group sent packetCan DatagramSocket Receive multicast PacketsJava Multicast receiver not working
What is a more techy Technical Writer job title that isn't cutesy or confusing?
Why can't fire hurt Daenerys but it did to Jon Snow in season 1?
Determine whether an integer is a palindrome
Marquee sign letters
How to ask rejected full-time candidates to apply to teach individual courses?
Pointing to problems without suggesting solutions
How does the body cool itself in a stillsuit?
Are there any irrational/transcendental numbers for which the distribution of decimal digits is not uniform?
Plotting a Maclaurin series
Diophantine equation 3^a+1=3^b+5^c
What are some likely causes to domain member PC losing contact to domain controller?
Keep at all times, the minus sign above aligned with minus sign below
Weaponising the Grasp-at-a-Distance spell
How could a hydrazine and N2O4 cloud (or it's reactants) show up in weather radar?
How can I prevent/balance waiting and turtling as a response to cooldown mechanics
Improvising over quartal voicings
What helicopter has the most rotor blades?
.bashrc alias for a command with fixed second parameter
Why does BitLocker not use RSA?
Statistical analysis applied to methods coming out of Machine Learning
Is a copyright notice with a non-existent name be invalid?
Why not use the yoke to control yaw, as well as pitch and roll?
Understanding piped commands in GNU/Linux
Why did Bronn offer to be Tyrion Lannister's champion in trial by combat?
Multicast between applications on the same host
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!Differences between HashMap and Hashtable?What is the difference between public, protected, package-private and private in Java?Finding the multicast IP that a datagram was sent toJava multicast socket not received out of localhostMulticastSocket constructors and binding to port or SocketAddressJava multiple multicast sockets in same group on same host and portReceiving Unicast on Multicast socketJava UDP multicast, determine which group sent packetCan DatagramSocket Receive multicast PacketsJava Multicast receiver not working
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
From what I've read, it should be possible for two applications on the same host to be able to send and receive datagrams via multicast. I was trying to implement this, using the following Java code (which is a slightly modified version of what is given in the Javadoc for MulticastSocket):
public static void main(String[] args) throws IOException
NetworkInterface nic = NetworkInterface.getByName("wlan4");
int port = 6789;
InetAddress group = InetAddress.getByName("228.5.6.7");
MulticastSocket s = new MulticastSocket(port);
s.setNetworkInterface(nic);
s.joinGroup(group);
if(args.length > 0 && args[0].equals("send"))
System.out.println("SEND MODE");
String msg = "Hello";
DatagramPacket hi = new DatagramPacket(msg.getBytes(), msg.length(),
group, port);
s.send(hi);
else
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
If I run the above code, giving send
as input argument, the program executes just fine, it sends the packet and then terminates. However if I want to receive a packet, the program is blocked by the receive method as it never gets a datagram. I tested this by running multiple instances of the application on my machine, both with one and several receivers and one sender. Non gets any message at any time.
If I, on the other hand let the application receive what it just sent (by running the receive method unconditionally of wheter the application is sending), it works fine for that application alone. This triggers me to believe that the JVM instance has an exclusive bind on that socket, disallowing others to use it (even if the option getReuseAddress()
returns true for MulticastSockets).
I'm running under Windows 10, and have verified that the UDP packet gets sent to the network using Wireshark, so I figured it has to do with that the packet is not delivered to the two applications.
What can I do in order to allow two applications to communicate over multicast on the same port number?
EDIT:
The overall idea is for a server to send a datagram to all listening clients on the network chosen (hence why the NIC is specified in the example as "wlan4"), irrespectively of where they are executed (e.g. on the same host as the server or not).
java network-programming multicast multicastsocket
add a comment |
From what I've read, it should be possible for two applications on the same host to be able to send and receive datagrams via multicast. I was trying to implement this, using the following Java code (which is a slightly modified version of what is given in the Javadoc for MulticastSocket):
public static void main(String[] args) throws IOException
NetworkInterface nic = NetworkInterface.getByName("wlan4");
int port = 6789;
InetAddress group = InetAddress.getByName("228.5.6.7");
MulticastSocket s = new MulticastSocket(port);
s.setNetworkInterface(nic);
s.joinGroup(group);
if(args.length > 0 && args[0].equals("send"))
System.out.println("SEND MODE");
String msg = "Hello";
DatagramPacket hi = new DatagramPacket(msg.getBytes(), msg.length(),
group, port);
s.send(hi);
else
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
If I run the above code, giving send
as input argument, the program executes just fine, it sends the packet and then terminates. However if I want to receive a packet, the program is blocked by the receive method as it never gets a datagram. I tested this by running multiple instances of the application on my machine, both with one and several receivers and one sender. Non gets any message at any time.
If I, on the other hand let the application receive what it just sent (by running the receive method unconditionally of wheter the application is sending), it works fine for that application alone. This triggers me to believe that the JVM instance has an exclusive bind on that socket, disallowing others to use it (even if the option getReuseAddress()
returns true for MulticastSockets).
I'm running under Windows 10, and have verified that the UDP packet gets sent to the network using Wireshark, so I figured it has to do with that the packet is not delivered to the two applications.
What can I do in order to allow two applications to communicate over multicast on the same port number?
EDIT:
The overall idea is for a server to send a datagram to all listening clients on the network chosen (hence why the NIC is specified in the example as "wlan4"), irrespectively of where they are executed (e.g. on the same host as the server or not).
java network-programming multicast multicastsocket
Why are you forcing the multicast socket to usewlan4
when all the required communication is within the localhost?
– user207421
Mar 9 at 2:14
Good point, and I realize that I might not have explained my overall intentions. The idea is for a sender to send a datagram to be caught by all clients on a network, irrespectively of whether the clients reside on the same host as the server or not.
– chrillof
Mar 9 at 13:21
Have you disabled multicast loopback? It seems to me that you are only receiving loopbacks, and that yourjoinGroup()
hasn't taken effect outside your localhost at all. Try just removing thesetNetworkInterface()
line.
– user207421
Mar 10 at 23:40
add a comment |
From what I've read, it should be possible for two applications on the same host to be able to send and receive datagrams via multicast. I was trying to implement this, using the following Java code (which is a slightly modified version of what is given in the Javadoc for MulticastSocket):
public static void main(String[] args) throws IOException
NetworkInterface nic = NetworkInterface.getByName("wlan4");
int port = 6789;
InetAddress group = InetAddress.getByName("228.5.6.7");
MulticastSocket s = new MulticastSocket(port);
s.setNetworkInterface(nic);
s.joinGroup(group);
if(args.length > 0 && args[0].equals("send"))
System.out.println("SEND MODE");
String msg = "Hello";
DatagramPacket hi = new DatagramPacket(msg.getBytes(), msg.length(),
group, port);
s.send(hi);
else
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
If I run the above code, giving send
as input argument, the program executes just fine, it sends the packet and then terminates. However if I want to receive a packet, the program is blocked by the receive method as it never gets a datagram. I tested this by running multiple instances of the application on my machine, both with one and several receivers and one sender. Non gets any message at any time.
If I, on the other hand let the application receive what it just sent (by running the receive method unconditionally of wheter the application is sending), it works fine for that application alone. This triggers me to believe that the JVM instance has an exclusive bind on that socket, disallowing others to use it (even if the option getReuseAddress()
returns true for MulticastSockets).
I'm running under Windows 10, and have verified that the UDP packet gets sent to the network using Wireshark, so I figured it has to do with that the packet is not delivered to the two applications.
What can I do in order to allow two applications to communicate over multicast on the same port number?
EDIT:
The overall idea is for a server to send a datagram to all listening clients on the network chosen (hence why the NIC is specified in the example as "wlan4"), irrespectively of where they are executed (e.g. on the same host as the server or not).
java network-programming multicast multicastsocket
From what I've read, it should be possible for two applications on the same host to be able to send and receive datagrams via multicast. I was trying to implement this, using the following Java code (which is a slightly modified version of what is given in the Javadoc for MulticastSocket):
public static void main(String[] args) throws IOException
NetworkInterface nic = NetworkInterface.getByName("wlan4");
int port = 6789;
InetAddress group = InetAddress.getByName("228.5.6.7");
MulticastSocket s = new MulticastSocket(port);
s.setNetworkInterface(nic);
s.joinGroup(group);
if(args.length > 0 && args[0].equals("send"))
System.out.println("SEND MODE");
String msg = "Hello";
DatagramPacket hi = new DatagramPacket(msg.getBytes(), msg.length(),
group, port);
s.send(hi);
else
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
If I run the above code, giving send
as input argument, the program executes just fine, it sends the packet and then terminates. However if I want to receive a packet, the program is blocked by the receive method as it never gets a datagram. I tested this by running multiple instances of the application on my machine, both with one and several receivers and one sender. Non gets any message at any time.
If I, on the other hand let the application receive what it just sent (by running the receive method unconditionally of wheter the application is sending), it works fine for that application alone. This triggers me to believe that the JVM instance has an exclusive bind on that socket, disallowing others to use it (even if the option getReuseAddress()
returns true for MulticastSockets).
I'm running under Windows 10, and have verified that the UDP packet gets sent to the network using Wireshark, so I figured it has to do with that the packet is not delivered to the two applications.
What can I do in order to allow two applications to communicate over multicast on the same port number?
EDIT:
The overall idea is for a server to send a datagram to all listening clients on the network chosen (hence why the NIC is specified in the example as "wlan4"), irrespectively of where they are executed (e.g. on the same host as the server or not).
java network-programming multicast multicastsocket
java network-programming multicast multicastsocket
edited Mar 10 at 23:09
chrillof
asked Mar 9 at 0:59
chrillofchrillof
206
206
Why are you forcing the multicast socket to usewlan4
when all the required communication is within the localhost?
– user207421
Mar 9 at 2:14
Good point, and I realize that I might not have explained my overall intentions. The idea is for a sender to send a datagram to be caught by all clients on a network, irrespectively of whether the clients reside on the same host as the server or not.
– chrillof
Mar 9 at 13:21
Have you disabled multicast loopback? It seems to me that you are only receiving loopbacks, and that yourjoinGroup()
hasn't taken effect outside your localhost at all. Try just removing thesetNetworkInterface()
line.
– user207421
Mar 10 at 23:40
add a comment |
Why are you forcing the multicast socket to usewlan4
when all the required communication is within the localhost?
– user207421
Mar 9 at 2:14
Good point, and I realize that I might not have explained my overall intentions. The idea is for a sender to send a datagram to be caught by all clients on a network, irrespectively of whether the clients reside on the same host as the server or not.
– chrillof
Mar 9 at 13:21
Have you disabled multicast loopback? It seems to me that you are only receiving loopbacks, and that yourjoinGroup()
hasn't taken effect outside your localhost at all. Try just removing thesetNetworkInterface()
line.
– user207421
Mar 10 at 23:40
Why are you forcing the multicast socket to use
wlan4
when all the required communication is within the localhost?– user207421
Mar 9 at 2:14
Why are you forcing the multicast socket to use
wlan4
when all the required communication is within the localhost?– user207421
Mar 9 at 2:14
Good point, and I realize that I might not have explained my overall intentions. The idea is for a sender to send a datagram to be caught by all clients on a network, irrespectively of whether the clients reside on the same host as the server or not.
– chrillof
Mar 9 at 13:21
Good point, and I realize that I might not have explained my overall intentions. The idea is for a sender to send a datagram to be caught by all clients on a network, irrespectively of whether the clients reside on the same host as the server or not.
– chrillof
Mar 9 at 13:21
Have you disabled multicast loopback? It seems to me that you are only receiving loopbacks, and that your
joinGroup()
hasn't taken effect outside your localhost at all. Try just removing the setNetworkInterface()
line.– user207421
Mar 10 at 23:40
Have you disabled multicast loopback? It seems to me that you are only receiving loopbacks, and that your
joinGroup()
hasn't taken effect outside your localhost at all. Try just removing the setNetworkInterface()
line.– user207421
Mar 10 at 23:40
add a comment |
1 Answer
1
active
oldest
votes
After some debugging, I realized that I could receive multicast packets from several applications if the application itself were sending and receiving multicast datagrams. It turns out that sending a packet to the multicast group somehow triggers this functionality. It seems like a bug to me.
However, in order to get the above example work as expected, I had to send (and discard) a first datagram to the multicast channel. I did this in the most simple way, by changing the else
block to the following:
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
s.send(new DatagramPacket("A".getBytes(), 1, group, port));
s.receive(recv);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
This doesn't seem right. NB You should usenew String(recv.getData(), 0, recv.getLength())
.
– user207421
Mar 10 at 23:41
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55072968%2fmulticast-between-applications-on-the-same-host%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
After some debugging, I realized that I could receive multicast packets from several applications if the application itself were sending and receiving multicast datagrams. It turns out that sending a packet to the multicast group somehow triggers this functionality. It seems like a bug to me.
However, in order to get the above example work as expected, I had to send (and discard) a first datagram to the multicast channel. I did this in the most simple way, by changing the else
block to the following:
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
s.send(new DatagramPacket("A".getBytes(), 1, group, port));
s.receive(recv);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
This doesn't seem right. NB You should usenew String(recv.getData(), 0, recv.getLength())
.
– user207421
Mar 10 at 23:41
add a comment |
After some debugging, I realized that I could receive multicast packets from several applications if the application itself were sending and receiving multicast datagrams. It turns out that sending a packet to the multicast group somehow triggers this functionality. It seems like a bug to me.
However, in order to get the above example work as expected, I had to send (and discard) a first datagram to the multicast channel. I did this in the most simple way, by changing the else
block to the following:
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
s.send(new DatagramPacket("A".getBytes(), 1, group, port));
s.receive(recv);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
This doesn't seem right. NB You should usenew String(recv.getData(), 0, recv.getLength())
.
– user207421
Mar 10 at 23:41
add a comment |
After some debugging, I realized that I could receive multicast packets from several applications if the application itself were sending and receiving multicast datagrams. It turns out that sending a packet to the multicast group somehow triggers this functionality. It seems like a bug to me.
However, in order to get the above example work as expected, I had to send (and discard) a first datagram to the multicast channel. I did this in the most simple way, by changing the else
block to the following:
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
s.send(new DatagramPacket("A".getBytes(), 1, group, port));
s.receive(recv);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
After some debugging, I realized that I could receive multicast packets from several applications if the application itself were sending and receiving multicast datagrams. It turns out that sending a packet to the multicast group somehow triggers this functionality. It seems like a bug to me.
However, in order to get the above example work as expected, I had to send (and discard) a first datagram to the multicast channel. I did this in the most simple way, by changing the else
block to the following:
byte[] buf = new byte[1000];
DatagramPacket recv = new DatagramPacket(buf, buf.length);
s.send(new DatagramPacket("A".getBytes(), 1, group, port));
s.receive(recv);
System.out.println("RECEIVE MODE");
s.receive(recv);
System.out.println(MessageFormat.format("Received: 0",
new String(recv.getData()).trim()));
s.leaveGroup(group);
answered Mar 10 at 23:09
chrillofchrillof
206
206
This doesn't seem right. NB You should usenew String(recv.getData(), 0, recv.getLength())
.
– user207421
Mar 10 at 23:41
add a comment |
This doesn't seem right. NB You should usenew String(recv.getData(), 0, recv.getLength())
.
– user207421
Mar 10 at 23:41
This doesn't seem right. NB You should use
new String(recv.getData(), 0, recv.getLength())
.– user207421
Mar 10 at 23:41
This doesn't seem right. NB You should use
new String(recv.getData(), 0, recv.getLength())
.– user207421
Mar 10 at 23:41
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55072968%2fmulticast-between-applications-on-the-same-host%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Why are you forcing the multicast socket to use
wlan4
when all the required communication is within the localhost?– user207421
Mar 9 at 2:14
Good point, and I realize that I might not have explained my overall intentions. The idea is for a sender to send a datagram to be caught by all clients on a network, irrespectively of whether the clients reside on the same host as the server or not.
– chrillof
Mar 9 at 13:21
Have you disabled multicast loopback? It seems to me that you are only receiving loopbacks, and that your
joinGroup()
hasn't taken effect outside your localhost at all. Try just removing thesetNetworkInterface()
line.– user207421
Mar 10 at 23:40