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Regex pattern to parse path with tabs and newlines?


Regex Named Groups in JavaMatch all occurrences of a regexA comprehensive regex for phone number validationHow to negate specific word in regex?RegEx match open tags except XHTML self-contained tagsHow to parse JSON in JavaRegex Pattern to Match, Excluding when… / Except betweenregex multiline not working on repeated patternsRegex multiple capture groups on same patternRegex to identify a full path nameRegex matching lines with escaped new line character






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0















I've a path dirntsubdir1ntsubdir2nttfile.ext that I want to process one segment at a time. For each segment, I want to know how many tabs precede it, and I want to have the rest of the path intact. For the given example



Iteration 1:



Preceding tabs: 0
Segment: dir
Rest: ntsubdir1ntsubdir2nttfile.ext


Iteration 2:



Preceding tabs: 1
Segment: subdir1
Rest: ntsubdir2nttfile.ext


Iteration 3:



Preceding tabs: 1
Segment: subdir2
Rest: nttfile.ext


Iteration 4:



Preceding tabs: 2
Segment: file.ext
Rest: ""


The pattern I came up with is ((?<=\R)\h*)(\H+). However, that is giving me tsubdir1n as the first match. What am I doing wrong?










share|improve this question




























    0















    I've a path dirntsubdir1ntsubdir2nttfile.ext that I want to process one segment at a time. For each segment, I want to know how many tabs precede it, and I want to have the rest of the path intact. For the given example



    Iteration 1:



    Preceding tabs: 0
    Segment: dir
    Rest: ntsubdir1ntsubdir2nttfile.ext


    Iteration 2:



    Preceding tabs: 1
    Segment: subdir1
    Rest: ntsubdir2nttfile.ext


    Iteration 3:



    Preceding tabs: 1
    Segment: subdir2
    Rest: nttfile.ext


    Iteration 4:



    Preceding tabs: 2
    Segment: file.ext
    Rest: ""


    The pattern I came up with is ((?<=\R)\h*)(\H+). However, that is giving me tsubdir1n as the first match. What am I doing wrong?










    share|improve this question
























      0












      0








      0








      I've a path dirntsubdir1ntsubdir2nttfile.ext that I want to process one segment at a time. For each segment, I want to know how many tabs precede it, and I want to have the rest of the path intact. For the given example



      Iteration 1:



      Preceding tabs: 0
      Segment: dir
      Rest: ntsubdir1ntsubdir2nttfile.ext


      Iteration 2:



      Preceding tabs: 1
      Segment: subdir1
      Rest: ntsubdir2nttfile.ext


      Iteration 3:



      Preceding tabs: 1
      Segment: subdir2
      Rest: nttfile.ext


      Iteration 4:



      Preceding tabs: 2
      Segment: file.ext
      Rest: ""


      The pattern I came up with is ((?<=\R)\h*)(\H+). However, that is giving me tsubdir1n as the first match. What am I doing wrong?










      share|improve this question














      I've a path dirntsubdir1ntsubdir2nttfile.ext that I want to process one segment at a time. For each segment, I want to know how many tabs precede it, and I want to have the rest of the path intact. For the given example



      Iteration 1:



      Preceding tabs: 0
      Segment: dir
      Rest: ntsubdir1ntsubdir2nttfile.ext


      Iteration 2:



      Preceding tabs: 1
      Segment: subdir1
      Rest: ntsubdir2nttfile.ext


      Iteration 3:



      Preceding tabs: 1
      Segment: subdir2
      Rest: nttfile.ext


      Iteration 4:



      Preceding tabs: 2
      Segment: file.ext
      Rest: ""


      The pattern I came up with is ((?<=\R)\h*)(\H+). However, that is giving me tsubdir1n as the first match. What am I doing wrong?







      java regex regex-lookarounds regex-group






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 8 at 2:17









      Abhijit SarkarAbhijit Sarkar

      7,77474396




      7,77474396






















          1 Answer
          1






          active

          oldest

          votes


















          1














          Since all sections are separated by line separator n you can simply use .+ to match them since by default dot . can't match line separators, so you are sure that it will stop before n (or any other line separator like r).



          You can also add some groups to separate tabs from actual segment like named group (?<tabs>t*) to match zero or more tabs at start of each match.



          To print rest of text after match simply substring after index of last matched character (you can obtain it via Matcher#end).



          To print string which will contain n and t (not as literals but as pair of backslash and letter) you can either manually replace each "n" with "\n" and "t" with "\t" or use utility class like StringEscapeUtils from org.apache.commons.lang which contains escapeJava method which does it for us.



          So your code can look like:



          String path = "dirntsubdir1ntsubdir2nttfile.ext";
          Pattern p = Pattern.compile("(?<tabs>t*)(?<segment>.+)");//dot can't match line separators
          Matcher m = p.matcher(path);
          int i = 1;
          while(m.find())
          System.out.println("iteration: " + i++);
          System.out.println("Preceding tabs: " + (m.group("tabs").length()));
          System.out.println("Segment: " + m.group("segment"));
          System.out.println("Rest: "+ StringEscapeUtils.escapeJava(path.substring(m.end())));
          System.out.println();



          Output:



          iteration: 1
          Preceding tabs: 0
          Segment: dir
          Rest: ntsubdir1ntsubdir2nttfile.ext

          iteration: 2
          Preceding tabs: 1
          Segment: subdir1
          Rest: ntsubdir2nttfile.ext

          iteration: 3
          Preceding tabs: 1
          Segment: subdir2
          Rest: nttfile.ext

          iteration: 4
          Preceding tabs: 2
          Segment: file.ext
          Rest:





          share|improve this answer

























          • Couple of comments: 1) StringEscapeUtils is now in commons-text, the one in commons-lang has been deprecated. 2) To literally print n, replace with \\n, not \n.

            – Abhijit Sarkar
            Mar 9 at 6:42







          • 1





            @AbhijitSarkar (1) thanks for update, (2) only if you are using replaceAll which supports regex where is metacharecter and require additional escaping. But if you use replace which doesn't support regex syntax and also replaces all matches replace("n", "\n") should work fine.

            – Pshemo
            Mar 9 at 10:28











          • You're correct, about replace. Can it be any more confusing, that both replace and replaceAll actually replace all?

            – Abhijit Sarkar
            Mar 9 at 20:42











          • @AbhijitSarkar Yes, naming of replacing methods is confusing. Probable rationale behind All suffix is that it emphasize difference between it and replaceFrist which also supports regex syntax. Confusing part is that other replacing methods: replace(char target, char replacement) and replace(CharSequence target, CharSequence replacement) don't use regex but also replace all occurrences of target.

            – Pshemo
            Mar 9 at 22:24












          • Alternative names could be replaceRegex and replaceFirstRegex which IMO would be less confusing but some could say that these names could be too long (which IMO is not the case since IDE would suggest them and people would autocomplete them, so we wouldn't really need more keystrokes). But that is just my opinion.

            – Pshemo
            Mar 9 at 22:29












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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Since all sections are separated by line separator n you can simply use .+ to match them since by default dot . can't match line separators, so you are sure that it will stop before n (or any other line separator like r).



          You can also add some groups to separate tabs from actual segment like named group (?<tabs>t*) to match zero or more tabs at start of each match.



          To print rest of text after match simply substring after index of last matched character (you can obtain it via Matcher#end).



          To print string which will contain n and t (not as literals but as pair of backslash and letter) you can either manually replace each "n" with "\n" and "t" with "\t" or use utility class like StringEscapeUtils from org.apache.commons.lang which contains escapeJava method which does it for us.



          So your code can look like:



          String path = "dirntsubdir1ntsubdir2nttfile.ext";
          Pattern p = Pattern.compile("(?<tabs>t*)(?<segment>.+)");//dot can't match line separators
          Matcher m = p.matcher(path);
          int i = 1;
          while(m.find())
          System.out.println("iteration: " + i++);
          System.out.println("Preceding tabs: " + (m.group("tabs").length()));
          System.out.println("Segment: " + m.group("segment"));
          System.out.println("Rest: "+ StringEscapeUtils.escapeJava(path.substring(m.end())));
          System.out.println();



          Output:



          iteration: 1
          Preceding tabs: 0
          Segment: dir
          Rest: ntsubdir1ntsubdir2nttfile.ext

          iteration: 2
          Preceding tabs: 1
          Segment: subdir1
          Rest: ntsubdir2nttfile.ext

          iteration: 3
          Preceding tabs: 1
          Segment: subdir2
          Rest: nttfile.ext

          iteration: 4
          Preceding tabs: 2
          Segment: file.ext
          Rest:





          share|improve this answer

























          • Couple of comments: 1) StringEscapeUtils is now in commons-text, the one in commons-lang has been deprecated. 2) To literally print n, replace with \\n, not \n.

            – Abhijit Sarkar
            Mar 9 at 6:42







          • 1





            @AbhijitSarkar (1) thanks for update, (2) only if you are using replaceAll which supports regex where is metacharecter and require additional escaping. But if you use replace which doesn't support regex syntax and also replaces all matches replace("n", "\n") should work fine.

            – Pshemo
            Mar 9 at 10:28











          • You're correct, about replace. Can it be any more confusing, that both replace and replaceAll actually replace all?

            – Abhijit Sarkar
            Mar 9 at 20:42











          • @AbhijitSarkar Yes, naming of replacing methods is confusing. Probable rationale behind All suffix is that it emphasize difference between it and replaceFrist which also supports regex syntax. Confusing part is that other replacing methods: replace(char target, char replacement) and replace(CharSequence target, CharSequence replacement) don't use regex but also replace all occurrences of target.

            – Pshemo
            Mar 9 at 22:24












          • Alternative names could be replaceRegex and replaceFirstRegex which IMO would be less confusing but some could say that these names could be too long (which IMO is not the case since IDE would suggest them and people would autocomplete them, so we wouldn't really need more keystrokes). But that is just my opinion.

            – Pshemo
            Mar 9 at 22:29
















          1














          Since all sections are separated by line separator n you can simply use .+ to match them since by default dot . can't match line separators, so you are sure that it will stop before n (or any other line separator like r).



          You can also add some groups to separate tabs from actual segment like named group (?<tabs>t*) to match zero or more tabs at start of each match.



          To print rest of text after match simply substring after index of last matched character (you can obtain it via Matcher#end).



          To print string which will contain n and t (not as literals but as pair of backslash and letter) you can either manually replace each "n" with "\n" and "t" with "\t" or use utility class like StringEscapeUtils from org.apache.commons.lang which contains escapeJava method which does it for us.



          So your code can look like:



          String path = "dirntsubdir1ntsubdir2nttfile.ext";
          Pattern p = Pattern.compile("(?<tabs>t*)(?<segment>.+)");//dot can't match line separators
          Matcher m = p.matcher(path);
          int i = 1;
          while(m.find())
          System.out.println("iteration: " + i++);
          System.out.println("Preceding tabs: " + (m.group("tabs").length()));
          System.out.println("Segment: " + m.group("segment"));
          System.out.println("Rest: "+ StringEscapeUtils.escapeJava(path.substring(m.end())));
          System.out.println();



          Output:



          iteration: 1
          Preceding tabs: 0
          Segment: dir
          Rest: ntsubdir1ntsubdir2nttfile.ext

          iteration: 2
          Preceding tabs: 1
          Segment: subdir1
          Rest: ntsubdir2nttfile.ext

          iteration: 3
          Preceding tabs: 1
          Segment: subdir2
          Rest: nttfile.ext

          iteration: 4
          Preceding tabs: 2
          Segment: file.ext
          Rest:





          share|improve this answer

























          • Couple of comments: 1) StringEscapeUtils is now in commons-text, the one in commons-lang has been deprecated. 2) To literally print n, replace with \\n, not \n.

            – Abhijit Sarkar
            Mar 9 at 6:42







          • 1





            @AbhijitSarkar (1) thanks for update, (2) only if you are using replaceAll which supports regex where is metacharecter and require additional escaping. But if you use replace which doesn't support regex syntax and also replaces all matches replace("n", "\n") should work fine.

            – Pshemo
            Mar 9 at 10:28











          • You're correct, about replace. Can it be any more confusing, that both replace and replaceAll actually replace all?

            – Abhijit Sarkar
            Mar 9 at 20:42











          • @AbhijitSarkar Yes, naming of replacing methods is confusing. Probable rationale behind All suffix is that it emphasize difference between it and replaceFrist which also supports regex syntax. Confusing part is that other replacing methods: replace(char target, char replacement) and replace(CharSequence target, CharSequence replacement) don't use regex but also replace all occurrences of target.

            – Pshemo
            Mar 9 at 22:24












          • Alternative names could be replaceRegex and replaceFirstRegex which IMO would be less confusing but some could say that these names could be too long (which IMO is not the case since IDE would suggest them and people would autocomplete them, so we wouldn't really need more keystrokes). But that is just my opinion.

            – Pshemo
            Mar 9 at 22:29














          1












          1








          1







          Since all sections are separated by line separator n you can simply use .+ to match them since by default dot . can't match line separators, so you are sure that it will stop before n (or any other line separator like r).



          You can also add some groups to separate tabs from actual segment like named group (?<tabs>t*) to match zero or more tabs at start of each match.



          To print rest of text after match simply substring after index of last matched character (you can obtain it via Matcher#end).



          To print string which will contain n and t (not as literals but as pair of backslash and letter) you can either manually replace each "n" with "\n" and "t" with "\t" or use utility class like StringEscapeUtils from org.apache.commons.lang which contains escapeJava method which does it for us.



          So your code can look like:



          String path = "dirntsubdir1ntsubdir2nttfile.ext";
          Pattern p = Pattern.compile("(?<tabs>t*)(?<segment>.+)");//dot can't match line separators
          Matcher m = p.matcher(path);
          int i = 1;
          while(m.find())
          System.out.println("iteration: " + i++);
          System.out.println("Preceding tabs: " + (m.group("tabs").length()));
          System.out.println("Segment: " + m.group("segment"));
          System.out.println("Rest: "+ StringEscapeUtils.escapeJava(path.substring(m.end())));
          System.out.println();



          Output:



          iteration: 1
          Preceding tabs: 0
          Segment: dir
          Rest: ntsubdir1ntsubdir2nttfile.ext

          iteration: 2
          Preceding tabs: 1
          Segment: subdir1
          Rest: ntsubdir2nttfile.ext

          iteration: 3
          Preceding tabs: 1
          Segment: subdir2
          Rest: nttfile.ext

          iteration: 4
          Preceding tabs: 2
          Segment: file.ext
          Rest:





          share|improve this answer















          Since all sections are separated by line separator n you can simply use .+ to match them since by default dot . can't match line separators, so you are sure that it will stop before n (or any other line separator like r).



          You can also add some groups to separate tabs from actual segment like named group (?<tabs>t*) to match zero or more tabs at start of each match.



          To print rest of text after match simply substring after index of last matched character (you can obtain it via Matcher#end).



          To print string which will contain n and t (not as literals but as pair of backslash and letter) you can either manually replace each "n" with "\n" and "t" with "\t" or use utility class like StringEscapeUtils from org.apache.commons.lang which contains escapeJava method which does it for us.



          So your code can look like:



          String path = "dirntsubdir1ntsubdir2nttfile.ext";
          Pattern p = Pattern.compile("(?<tabs>t*)(?<segment>.+)");//dot can't match line separators
          Matcher m = p.matcher(path);
          int i = 1;
          while(m.find())
          System.out.println("iteration: " + i++);
          System.out.println("Preceding tabs: " + (m.group("tabs").length()));
          System.out.println("Segment: " + m.group("segment"));
          System.out.println("Rest: "+ StringEscapeUtils.escapeJava(path.substring(m.end())));
          System.out.println();



          Output:



          iteration: 1
          Preceding tabs: 0
          Segment: dir
          Rest: ntsubdir1ntsubdir2nttfile.ext

          iteration: 2
          Preceding tabs: 1
          Segment: subdir1
          Rest: ntsubdir2nttfile.ext

          iteration: 3
          Preceding tabs: 1
          Segment: subdir2
          Rest: nttfile.ext

          iteration: 4
          Preceding tabs: 2
          Segment: file.ext
          Rest:






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 8 at 14:03

























          answered Mar 8 at 2:49









          PshemoPshemo

          96.1k15134194




          96.1k15134194












          • Couple of comments: 1) StringEscapeUtils is now in commons-text, the one in commons-lang has been deprecated. 2) To literally print n, replace with \\n, not \n.

            – Abhijit Sarkar
            Mar 9 at 6:42







          • 1





            @AbhijitSarkar (1) thanks for update, (2) only if you are using replaceAll which supports regex where is metacharecter and require additional escaping. But if you use replace which doesn't support regex syntax and also replaces all matches replace("n", "\n") should work fine.

            – Pshemo
            Mar 9 at 10:28











          • You're correct, about replace. Can it be any more confusing, that both replace and replaceAll actually replace all?

            – Abhijit Sarkar
            Mar 9 at 20:42











          • @AbhijitSarkar Yes, naming of replacing methods is confusing. Probable rationale behind All suffix is that it emphasize difference between it and replaceFrist which also supports regex syntax. Confusing part is that other replacing methods: replace(char target, char replacement) and replace(CharSequence target, CharSequence replacement) don't use regex but also replace all occurrences of target.

            – Pshemo
            Mar 9 at 22:24












          • Alternative names could be replaceRegex and replaceFirstRegex which IMO would be less confusing but some could say that these names could be too long (which IMO is not the case since IDE would suggest them and people would autocomplete them, so we wouldn't really need more keystrokes). But that is just my opinion.

            – Pshemo
            Mar 9 at 22:29


















          • Couple of comments: 1) StringEscapeUtils is now in commons-text, the one in commons-lang has been deprecated. 2) To literally print n, replace with \\n, not \n.

            – Abhijit Sarkar
            Mar 9 at 6:42







          • 1





            @AbhijitSarkar (1) thanks for update, (2) only if you are using replaceAll which supports regex where is metacharecter and require additional escaping. But if you use replace which doesn't support regex syntax and also replaces all matches replace("n", "\n") should work fine.

            – Pshemo
            Mar 9 at 10:28











          • You're correct, about replace. Can it be any more confusing, that both replace and replaceAll actually replace all?

            – Abhijit Sarkar
            Mar 9 at 20:42











          • @AbhijitSarkar Yes, naming of replacing methods is confusing. Probable rationale behind All suffix is that it emphasize difference between it and replaceFrist which also supports regex syntax. Confusing part is that other replacing methods: replace(char target, char replacement) and replace(CharSequence target, CharSequence replacement) don't use regex but also replace all occurrences of target.

            – Pshemo
            Mar 9 at 22:24












          • Alternative names could be replaceRegex and replaceFirstRegex which IMO would be less confusing but some could say that these names could be too long (which IMO is not the case since IDE would suggest them and people would autocomplete them, so we wouldn't really need more keystrokes). But that is just my opinion.

            – Pshemo
            Mar 9 at 22:29

















          Couple of comments: 1) StringEscapeUtils is now in commons-text, the one in commons-lang has been deprecated. 2) To literally print n, replace with \\n, not \n.

          – Abhijit Sarkar
          Mar 9 at 6:42






          Couple of comments: 1) StringEscapeUtils is now in commons-text, the one in commons-lang has been deprecated. 2) To literally print n, replace with \\n, not \n.

          – Abhijit Sarkar
          Mar 9 at 6:42





          1




          1





          @AbhijitSarkar (1) thanks for update, (2) only if you are using replaceAll which supports regex where is metacharecter and require additional escaping. But if you use replace which doesn't support regex syntax and also replaces all matches replace("n", "\n") should work fine.

          – Pshemo
          Mar 9 at 10:28





          @AbhijitSarkar (1) thanks for update, (2) only if you are using replaceAll which supports regex where is metacharecter and require additional escaping. But if you use replace which doesn't support regex syntax and also replaces all matches replace("n", "\n") should work fine.

          – Pshemo
          Mar 9 at 10:28













          You're correct, about replace. Can it be any more confusing, that both replace and replaceAll actually replace all?

          – Abhijit Sarkar
          Mar 9 at 20:42





          You're correct, about replace. Can it be any more confusing, that both replace and replaceAll actually replace all?

          – Abhijit Sarkar
          Mar 9 at 20:42













          @AbhijitSarkar Yes, naming of replacing methods is confusing. Probable rationale behind All suffix is that it emphasize difference between it and replaceFrist which also supports regex syntax. Confusing part is that other replacing methods: replace(char target, char replacement) and replace(CharSequence target, CharSequence replacement) don't use regex but also replace all occurrences of target.

          – Pshemo
          Mar 9 at 22:24






          @AbhijitSarkar Yes, naming of replacing methods is confusing. Probable rationale behind All suffix is that it emphasize difference between it and replaceFrist which also supports regex syntax. Confusing part is that other replacing methods: replace(char target, char replacement) and replace(CharSequence target, CharSequence replacement) don't use regex but also replace all occurrences of target.

          – Pshemo
          Mar 9 at 22:24














          Alternative names could be replaceRegex and replaceFirstRegex which IMO would be less confusing but some could say that these names could be too long (which IMO is not the case since IDE would suggest them and people would autocomplete them, so we wouldn't really need more keystrokes). But that is just my opinion.

          – Pshemo
          Mar 9 at 22:29






          Alternative names could be replaceRegex and replaceFirstRegex which IMO would be less confusing but some could say that these names could be too long (which IMO is not the case since IDE would suggest them and people would autocomplete them, so we wouldn't really need more keystrokes). But that is just my opinion.

          – Pshemo
          Mar 9 at 22:29




















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