How to get latest Snapshot for a volume in AWS using API The Next CEO of Stack OverflowGrowing Amazon EBS Volume sizesHow to automatically snapshot a volume of an Amazon EC2 instance?Creating a snapshot including description via AWS Lambdaget the latest aws volume snapshot-id using python3 and boto3why don’t we see snap id in Dashboard Ec2 ->Volumes( Snapshot column) although Snapshot exist in ConsoleHow to get the end time of AWS EBS volume snapshot ? I want to find out the time when the snapshot completedHow to take EBS snapshot in Boto3 only for running instances?How to get VolumeId from the key BlockDeviceMappings (boto3 get volume info for ec2)How to retrieve all snapshots related to a AWS EC2 instance using BOTO3 Python?Getting snapshot cost based on tags

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How to get latest Snapshot for a volume in AWS using API



The Next CEO of Stack OverflowGrowing Amazon EBS Volume sizesHow to automatically snapshot a volume of an Amazon EC2 instance?Creating a snapshot including description via AWS Lambdaget the latest aws volume snapshot-id using python3 and boto3why don’t we see snap id in Dashboard Ec2 ->Volumes( Snapshot column) although Snapshot exist in ConsoleHow to get the end time of AWS EBS volume snapshot ? I want to find out the time when the snapshot completedHow to take EBS snapshot in Boto3 only for running instances?How to get VolumeId from the key BlockDeviceMappings (boto3 get volume info for ec2)How to retrieve all snapshots related to a AWS EC2 instance using BOTO3 Python?Getting snapshot cost based on tags










1















I want only the latest snapshot for a specific volume.



'response_v=boto3.client("ec2").describe_snapshots(Filters=["Name":"volume-id","Values":["vol-fffffffffff"]])'



How can it be done?










share|improve this question


























    1















    I want only the latest snapshot for a specific volume.



    'response_v=boto3.client("ec2").describe_snapshots(Filters=["Name":"volume-id","Values":["vol-fffffffffff"]])'



    How can it be done?










    share|improve this question
























      1












      1








      1








      I want only the latest snapshot for a specific volume.



      'response_v=boto3.client("ec2").describe_snapshots(Filters=["Name":"volume-id","Values":["vol-fffffffffff"]])'



      How can it be done?










      share|improve this question














      I want only the latest snapshot for a specific volume.



      'response_v=boto3.client("ec2").describe_snapshots(Filters=["Name":"volume-id","Values":["vol-fffffffffff"]])'



      How can it be done?







      python-3.x amazon-web-services boto3






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 7 at 14:00









      Tushar RaichandTushar Raichand

      83




      83






















          1 Answer
          1






          active

          oldest

          votes


















          0














          It looks like the describe_snapshots method returns the newest one first but you really shouldn't count on that.



          I think you can safely rely on the StartTime field, looking for the greatest value for all snapshots returned.




          Snapshots occur asynchronously; the point-in-time snapshot is created immediately




          Because of that the "largest" StartTime will be the latest snapshot



          I wrote this bit of code to print the snapshot_id with the latest snapshot start time. My python-fu is not the greatest but this works.



          import boto3
          import datetime
          import pytz

          utc = pytz.UTC
          starttime=datetime.datetime(1,1,1,tzinfo=utc)
          snap_id = ""
          volume_id = "<put your volume id here or write something more elegant to pass it in>"

          region = 'us-east-1'
          session = boto3.Session(profile_name='default')

          ec2 = session.client('ec2', region_name=region)

          response = ec2.describe_snapshots(Filters=["Name":"volume-id","Values":[volume_id]])

          # print(response['Snapshots'])
          for snap in response['Snapshots']:
          if snap['StartTime'] > starttime:
          snap_id = snap['SnapshotId']
          starttime= snap['StartTime']

          print(snap_id)


          References:



          https://docs.aws.amazon.com/AWSEC2/latest/UserGuide/ebs-creating-snapshot.html






          share|improve this answer























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            1 Answer
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            1 Answer
            1






            active

            oldest

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            active

            oldest

            votes






            active

            oldest

            votes









            0














            It looks like the describe_snapshots method returns the newest one first but you really shouldn't count on that.



            I think you can safely rely on the StartTime field, looking for the greatest value for all snapshots returned.




            Snapshots occur asynchronously; the point-in-time snapshot is created immediately




            Because of that the "largest" StartTime will be the latest snapshot



            I wrote this bit of code to print the snapshot_id with the latest snapshot start time. My python-fu is not the greatest but this works.



            import boto3
            import datetime
            import pytz

            utc = pytz.UTC
            starttime=datetime.datetime(1,1,1,tzinfo=utc)
            snap_id = ""
            volume_id = "<put your volume id here or write something more elegant to pass it in>"

            region = 'us-east-1'
            session = boto3.Session(profile_name='default')

            ec2 = session.client('ec2', region_name=region)

            response = ec2.describe_snapshots(Filters=["Name":"volume-id","Values":[volume_id]])

            # print(response['Snapshots'])
            for snap in response['Snapshots']:
            if snap['StartTime'] > starttime:
            snap_id = snap['SnapshotId']
            starttime= snap['StartTime']

            print(snap_id)


            References:



            https://docs.aws.amazon.com/AWSEC2/latest/UserGuide/ebs-creating-snapshot.html






            share|improve this answer



























              0














              It looks like the describe_snapshots method returns the newest one first but you really shouldn't count on that.



              I think you can safely rely on the StartTime field, looking for the greatest value for all snapshots returned.




              Snapshots occur asynchronously; the point-in-time snapshot is created immediately




              Because of that the "largest" StartTime will be the latest snapshot



              I wrote this bit of code to print the snapshot_id with the latest snapshot start time. My python-fu is not the greatest but this works.



              import boto3
              import datetime
              import pytz

              utc = pytz.UTC
              starttime=datetime.datetime(1,1,1,tzinfo=utc)
              snap_id = ""
              volume_id = "<put your volume id here or write something more elegant to pass it in>"

              region = 'us-east-1'
              session = boto3.Session(profile_name='default')

              ec2 = session.client('ec2', region_name=region)

              response = ec2.describe_snapshots(Filters=["Name":"volume-id","Values":[volume_id]])

              # print(response['Snapshots'])
              for snap in response['Snapshots']:
              if snap['StartTime'] > starttime:
              snap_id = snap['SnapshotId']
              starttime= snap['StartTime']

              print(snap_id)


              References:



              https://docs.aws.amazon.com/AWSEC2/latest/UserGuide/ebs-creating-snapshot.html






              share|improve this answer

























                0












                0








                0







                It looks like the describe_snapshots method returns the newest one first but you really shouldn't count on that.



                I think you can safely rely on the StartTime field, looking for the greatest value for all snapshots returned.




                Snapshots occur asynchronously; the point-in-time snapshot is created immediately




                Because of that the "largest" StartTime will be the latest snapshot



                I wrote this bit of code to print the snapshot_id with the latest snapshot start time. My python-fu is not the greatest but this works.



                import boto3
                import datetime
                import pytz

                utc = pytz.UTC
                starttime=datetime.datetime(1,1,1,tzinfo=utc)
                snap_id = ""
                volume_id = "<put your volume id here or write something more elegant to pass it in>"

                region = 'us-east-1'
                session = boto3.Session(profile_name='default')

                ec2 = session.client('ec2', region_name=region)

                response = ec2.describe_snapshots(Filters=["Name":"volume-id","Values":[volume_id]])

                # print(response['Snapshots'])
                for snap in response['Snapshots']:
                if snap['StartTime'] > starttime:
                snap_id = snap['SnapshotId']
                starttime= snap['StartTime']

                print(snap_id)


                References:



                https://docs.aws.amazon.com/AWSEC2/latest/UserGuide/ebs-creating-snapshot.html






                share|improve this answer













                It looks like the describe_snapshots method returns the newest one first but you really shouldn't count on that.



                I think you can safely rely on the StartTime field, looking for the greatest value for all snapshots returned.




                Snapshots occur asynchronously; the point-in-time snapshot is created immediately




                Because of that the "largest" StartTime will be the latest snapshot



                I wrote this bit of code to print the snapshot_id with the latest snapshot start time. My python-fu is not the greatest but this works.



                import boto3
                import datetime
                import pytz

                utc = pytz.UTC
                starttime=datetime.datetime(1,1,1,tzinfo=utc)
                snap_id = ""
                volume_id = "<put your volume id here or write something more elegant to pass it in>"

                region = 'us-east-1'
                session = boto3.Session(profile_name='default')

                ec2 = session.client('ec2', region_name=region)

                response = ec2.describe_snapshots(Filters=["Name":"volume-id","Values":[volume_id]])

                # print(response['Snapshots'])
                for snap in response['Snapshots']:
                if snap['StartTime'] > starttime:
                snap_id = snap['SnapshotId']
                starttime= snap['StartTime']

                print(snap_id)


                References:



                https://docs.aws.amazon.com/AWSEC2/latest/UserGuide/ebs-creating-snapshot.html







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 7 at 16:54









                kenlukaskenlukas

                1,55641418




                1,55641418





























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