Image loaded wrong by opencv The Next CEO of Stack OverflowHow to sharpen an image in OpenCV?Simple Digit Recognition OCR in OpenCV-PythonSave plot to image file instead of displaying it using MatplotlibImage Processing: Algorithm Improvement for 'Coca-Cola Can' RecognitionChecking images for similarity with OpenCVHow to crop an image in OpenCV using PythonSubtracting Background From Image using Opencv in PythonOpenCV giving wrong color to colored images on loadingOpenCV python layer is not working with caffe/digits frameworkDjango python-accept two images from post method, combine those images in opencv and then json response the final image
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Image loaded wrong by opencv
The Next CEO of Stack OverflowHow to sharpen an image in OpenCV?Simple Digit Recognition OCR in OpenCV-PythonSave plot to image file instead of displaying it using MatplotlibImage Processing: Algorithm Improvement for 'Coca-Cola Can' RecognitionChecking images for similarity with OpenCVHow to crop an image in OpenCV using PythonSubtracting Background From Image using Opencv in PythonOpenCV giving wrong color to colored images on loadingOpenCV python layer is not working with caffe/digits frameworkDjango python-accept two images from post method, combine those images in opencv and then json response the final image
Disaster!
As you can see, the image isn't quite loaded correctly. The original:
The code:
import cv2
import imutils
a=imutils.url_to_image("https://www.google.com/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png", readFlag=-1)
cv2.imshow("goog", a)
cv2.waitKey()
The implementation of url_to_image in imutils:
def url_to_image(url, readFlag=cv2.IMREAD_COLOR):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, readFlag)
# return the image
return image
I also tried readFlag=cv2.IMREAD_UNCHANGED, but that didn't do the trick either.
please send help
python opencv
asked Mar 7 at 14:24
Kelvin WangKelvin Wang
769
add a comment |
Disaster!
As you can see, the image isn't quite loaded correctly. The original:
The code:
import cv2
import imutils
a=imutils.url_to_image("https://www.google.com/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png", readFlag=-1)
cv2.imshow("goog", a)
cv2.waitKey()
The implementation of url_to_image in imutils:
def url_to_image(url, readFlag=cv2.IMREAD_COLOR):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, readFlag)
# return the image
return image
I also tried readFlag=cv2.IMREAD_UNCHANGED, but that didn't do the trick either.
please send help
python opencv
asked Mar 7 at 14:24
Kelvin WangKelvin Wang
769
add a comment |
Disaster!
As you can see, the image isn't quite loaded correctly. The original:
The code:
import cv2
import imutils
a=imutils.url_to_image("https://www.google.com/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png", readFlag=-1)
cv2.imshow("goog", a)
cv2.waitKey()
The implementation of url_to_image in imutils:
def url_to_image(url, readFlag=cv2.IMREAD_COLOR):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, readFlag)
# return the image
return image
I also tried readFlag=cv2.IMREAD_UNCHANGED, but that didn't do the trick either.
please send help
python opencv
asked Mar 7 at 14:24
Kelvin WangKelvin Wang
769
Disaster!
As you can see, the image isn't quite loaded correctly. The original:
The code:
import cv2
import imutils
a=imutils.url_to_image("https://www.google.com/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png", readFlag=-1)
cv2.imshow("goog", a)
cv2.waitKey()
The implementation of url_to_image in imutils:
def url_to_image(url, readFlag=cv2.IMREAD_COLOR):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, readFlag)
# return the image
return image
I also tried readFlag=cv2.IMREAD_UNCHANGED, but that didn't do the trick either.
please send help
python opencv
python opencv
asked Mar 7 at 14:24
Kelvin WangKelvin Wang
769
asked Mar 7 at 14:24
Kelvin WangKelvin Wang
769
asked Mar 7 at 14:24
Kelvin WangKelvin Wang
769
asked Mar 7 at 14:24
Kelvin WangKelvin Wang
769
asked Mar 7 at 14:24
Kelvin WangKelvin Wang
769
769
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
alright gang we did it
so I tried another version of displaying:
plt.figure("Correct")
plt.imshow(imutils.opencv2matplotlib(a))
plt.show()
No luck it would appear. But then, looking into the opencv2matplotlib source, we find:
def opencv2matplotlib(image):
# OpenCV represents images in BGR order; however, Matplotlib
# expects the image in RGB order, so simply convert from BGR
# to RGB and return
return cv2.cvtColor(image, cv2.COLOR_BGR2RGB)
Aha, but we have 4 channel color (alpha), so by common sense we need cv2.COLOR_BGRA2RGBA not cv2.COLOR_BGR2RGB!!
Testing this theory:
plt.figure("Correct")
plt.imshow(cv2.cvtColor(a, cv2.COLOR_BGRA2RGBA))
plt.show()
We get...
Whoop dee doop!
answered Mar 7 at 14:44
Kelvin WangKelvin Wang
769
why don't you use urllib
– Faizan Khan
Mar 7 at 14:48
I have a solution to this. Do you still need it?
– Faizan Khan
Mar 7 at 14:48
you won't use matplotlib in that case. rather you'll be using simple imshow(img) to display the image
– Faizan Khan
Mar 7 at 14:49
? urllib is used. urlopen is under namespace urllib.request also, cv2.imdecode needs to be called with flag of -1 or it doesn't even write to file correctly
– Kelvin Wang
Mar 7 at 15:04
add a comment |
# import the necessary packages
import numpy as np
import urllib
import cv2
def url_to_image(url):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urllib.request.urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, cv2.IMREAD_COLOR)
# return the image
return image
# initialize the list of image URLs to download
url="http://i.dailymail.co.uk/i/pix/2015/09/01/18/2BE1E88B00000578-3218613-image-m-5_1441127035222.jpg"
print ("downloading %s" % (url))
image = url_to_image(url)
cv2.imshow("Image", image)
cv2.waitKey(0)
And the output is:
answered Mar 7 at 14:55
Faizan KhanFaizan Khan
353312
This implementation fails on the target url. google.com/images/branding/googlelogo/2x/…
– Kelvin Wang
Mar 7 at 15:03
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
alright gang we did it
so I tried another version of displaying:
plt.figure("Correct")
plt.imshow(imutils.opencv2matplotlib(a))
plt.show()
No luck it would appear. But then, looking into the opencv2matplotlib source, we find:
def opencv2matplotlib(image):
# OpenCV represents images in BGR order; however, Matplotlib
# expects the image in RGB order, so simply convert from BGR
# to RGB and return
return cv2.cvtColor(image, cv2.COLOR_BGR2RGB)
Aha, but we have 4 channel color (alpha), so by common sense we need cv2.COLOR_BGRA2RGBA not cv2.COLOR_BGR2RGB!!
Testing this theory:
plt.figure("Correct")
plt.imshow(cv2.cvtColor(a, cv2.COLOR_BGRA2RGBA))
plt.show()
We get...
Whoop dee doop!
answered Mar 7 at 14:44
Kelvin WangKelvin Wang
769
why don't you use urllib
– Faizan Khan
Mar 7 at 14:48
I have a solution to this. Do you still need it?
– Faizan Khan
Mar 7 at 14:48
you won't use matplotlib in that case. rather you'll be using simple imshow(img) to display the image
– Faizan Khan
Mar 7 at 14:49
? urllib is used. urlopen is under namespace urllib.request also, cv2.imdecode needs to be called with flag of -1 or it doesn't even write to file correctly
– Kelvin Wang
Mar 7 at 15:04
add a comment |
alright gang we did it
so I tried another version of displaying:
plt.figure("Correct")
plt.imshow(imutils.opencv2matplotlib(a))
plt.show()
No luck it would appear. But then, looking into the opencv2matplotlib source, we find:
def opencv2matplotlib(image):
# OpenCV represents images in BGR order; however, Matplotlib
# expects the image in RGB order, so simply convert from BGR
# to RGB and return
return cv2.cvtColor(image, cv2.COLOR_BGR2RGB)
Aha, but we have 4 channel color (alpha), so by common sense we need cv2.COLOR_BGRA2RGBA not cv2.COLOR_BGR2RGB!!
Testing this theory:
plt.figure("Correct")
plt.imshow(cv2.cvtColor(a, cv2.COLOR_BGRA2RGBA))
plt.show()
We get...
Whoop dee doop!
answered Mar 7 at 14:44
Kelvin WangKelvin Wang
769
why don't you use urllib
– Faizan Khan
Mar 7 at 14:48
I have a solution to this. Do you still need it?
– Faizan Khan
Mar 7 at 14:48
you won't use matplotlib in that case. rather you'll be using simple imshow(img) to display the image
– Faizan Khan
Mar 7 at 14:49
? urllib is used. urlopen is under namespace urllib.request also, cv2.imdecode needs to be called with flag of -1 or it doesn't even write to file correctly
– Kelvin Wang
Mar 7 at 15:04
add a comment |
alright gang we did it
so I tried another version of displaying:
plt.figure("Correct")
plt.imshow(imutils.opencv2matplotlib(a))
plt.show()
No luck it would appear. But then, looking into the opencv2matplotlib source, we find:
def opencv2matplotlib(image):
# OpenCV represents images in BGR order; however, Matplotlib
# expects the image in RGB order, so simply convert from BGR
# to RGB and return
return cv2.cvtColor(image, cv2.COLOR_BGR2RGB)
Aha, but we have 4 channel color (alpha), so by common sense we need cv2.COLOR_BGRA2RGBA not cv2.COLOR_BGR2RGB!!
Testing this theory:
plt.figure("Correct")
plt.imshow(cv2.cvtColor(a, cv2.COLOR_BGRA2RGBA))
plt.show()
We get...
Whoop dee doop!
answered Mar 7 at 14:44
Kelvin WangKelvin Wang
769
alright gang we did it
so I tried another version of displaying:
plt.figure("Correct")
plt.imshow(imutils.opencv2matplotlib(a))
plt.show()
No luck it would appear. But then, looking into the opencv2matplotlib source, we find:
def opencv2matplotlib(image):
# OpenCV represents images in BGR order; however, Matplotlib
# expects the image in RGB order, so simply convert from BGR
# to RGB and return
return cv2.cvtColor(image, cv2.COLOR_BGR2RGB)
Aha, but we have 4 channel color (alpha), so by common sense we need cv2.COLOR_BGRA2RGBA not cv2.COLOR_BGR2RGB!!
Testing this theory:
plt.figure("Correct")
plt.imshow(cv2.cvtColor(a, cv2.COLOR_BGRA2RGBA))
plt.show()
We get...
Whoop dee doop!
answered Mar 7 at 14:44
Kelvin WangKelvin Wang
769
answered Mar 7 at 14:44
Kelvin WangKelvin Wang
769
answered Mar 7 at 14:44
Kelvin WangKelvin Wang
769
answered Mar 7 at 14:44
Kelvin WangKelvin Wang
769
769
why don't you use urllib
– Faizan Khan
Mar 7 at 14:48
I have a solution to this. Do you still need it?
– Faizan Khan
Mar 7 at 14:48
you won't use matplotlib in that case. rather you'll be using simple imshow(img) to display the image
– Faizan Khan
Mar 7 at 14:49
? urllib is used. urlopen is under namespace urllib.request also, cv2.imdecode needs to be called with flag of -1 or it doesn't even write to file correctly
– Kelvin Wang
Mar 7 at 15:04
add a comment |
why don't you use urllib
– Faizan Khan
Mar 7 at 14:48
I have a solution to this. Do you still need it?
– Faizan Khan
Mar 7 at 14:48
you won't use matplotlib in that case. rather you'll be using simple imshow(img) to display the image
– Faizan Khan
Mar 7 at 14:49
? urllib is used. urlopen is under namespace urllib.request also, cv2.imdecode needs to be called with flag of -1 or it doesn't even write to file correctly
– Kelvin Wang
Mar 7 at 15:04
why don't you use urllib
– Faizan Khan
Mar 7 at 14:48
why don't you use urllib
– Faizan Khan
Mar 7 at 14:48
I have a solution to this. Do you still need it?
– Faizan Khan
Mar 7 at 14:48
I have a solution to this. Do you still need it?
– Faizan Khan
Mar 7 at 14:48
you won't use matplotlib in that case. rather you'll be using simple imshow(img) to display the image
– Faizan Khan
Mar 7 at 14:49
you won't use matplotlib in that case. rather you'll be using simple imshow(img) to display the image
– Faizan Khan
Mar 7 at 14:49
? urllib is used. urlopen is under namespace urllib.request also, cv2.imdecode needs to be called with flag of -1 or it doesn't even write to file correctly
– Kelvin Wang
Mar 7 at 15:04
? urllib is used. urlopen is under namespace urllib.request also, cv2.imdecode needs to be called with flag of -1 or it doesn't even write to file correctly
– Kelvin Wang
Mar 7 at 15:04
add a comment |
# import the necessary packages
import numpy as np
import urllib
import cv2
def url_to_image(url):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urllib.request.urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, cv2.IMREAD_COLOR)
# return the image
return image
# initialize the list of image URLs to download
url="http://i.dailymail.co.uk/i/pix/2015/09/01/18/2BE1E88B00000578-3218613-image-m-5_1441127035222.jpg"
print ("downloading %s" % (url))
image = url_to_image(url)
cv2.imshow("Image", image)
cv2.waitKey(0)
And the output is:
answered Mar 7 at 14:55
Faizan KhanFaizan Khan
353312
This implementation fails on the target url. google.com/images/branding/googlelogo/2x/…
– Kelvin Wang
Mar 7 at 15:03
add a comment |
# import the necessary packages
import numpy as np
import urllib
import cv2
def url_to_image(url):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urllib.request.urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, cv2.IMREAD_COLOR)
# return the image
return image
# initialize the list of image URLs to download
url="http://i.dailymail.co.uk/i/pix/2015/09/01/18/2BE1E88B00000578-3218613-image-m-5_1441127035222.jpg"
print ("downloading %s" % (url))
image = url_to_image(url)
cv2.imshow("Image", image)
cv2.waitKey(0)
And the output is:
answered Mar 7 at 14:55
Faizan KhanFaizan Khan
353312
This implementation fails on the target url. google.com/images/branding/googlelogo/2x/…
– Kelvin Wang
Mar 7 at 15:03
add a comment |
# import the necessary packages
import numpy as np
import urllib
import cv2
def url_to_image(url):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urllib.request.urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, cv2.IMREAD_COLOR)
# return the image
return image
# initialize the list of image URLs to download
url="http://i.dailymail.co.uk/i/pix/2015/09/01/18/2BE1E88B00000578-3218613-image-m-5_1441127035222.jpg"
print ("downloading %s" % (url))
image = url_to_image(url)
cv2.imshow("Image", image)
cv2.waitKey(0)
And the output is:
answered Mar 7 at 14:55
Faizan KhanFaizan Khan
353312
# import the necessary packages
import numpy as np
import urllib
import cv2
def url_to_image(url):
# download the image, convert it to a NumPy array, and then read
# it into OpenCV format
resp = urllib.request.urlopen(url)
image = np.asarray(bytearray(resp.read()), dtype="uint8")
image = cv2.imdecode(image, cv2.IMREAD_COLOR)
# return the image
return image
# initialize the list of image URLs to download
url="http://i.dailymail.co.uk/i/pix/2015/09/01/18/2BE1E88B00000578-3218613-image-m-5_1441127035222.jpg"
print ("downloading %s" % (url))
image = url_to_image(url)
cv2.imshow("Image", image)
cv2.waitKey(0)
And the output is:
answered Mar 7 at 14:55
Faizan KhanFaizan Khan
353312
answered Mar 7 at 14:55
Faizan KhanFaizan Khan
353312
answered Mar 7 at 14:55
Faizan KhanFaizan Khan
353312
answered Mar 7 at 14:55
Faizan KhanFaizan Khan
353312
353312
This implementation fails on the target url. google.com/images/branding/googlelogo/2x/…
– Kelvin Wang
Mar 7 at 15:03
add a comment |
This implementation fails on the target url. google.com/images/branding/googlelogo/2x/…
– Kelvin Wang
Mar 7 at 15:03
This implementation fails on the target url. google.com/images/branding/googlelogo/2x/…
– Kelvin Wang
Mar 7 at 15:03
This implementation fails on the target url. google.com/images/branding/googlelogo/2x/…
– Kelvin Wang
Mar 7 at 15:03
add a comment |
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