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Display Object data if parameters not defined

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0

So let's say I want to display name inside object, That would be

echo $object->name

If I want to display age of specific person, that would be

echo $object->name->dave->age

And I can display a lot of things.

However, What should I do if I don't know parameters which to display?

So let's say dave passed to me, and right now in $person

That would be something like

echo $object->name->$person->age

However I can't do that.

Is there any way to do that?

php

share|improve this question

edited Mar 8 at 7:58

Rostyslav

asked Mar 8 at 5:47

RostyslavRostyslav

366

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Need more detail, your question is not clear.
  
  – Ankur Tiwari
  Mar 8 at 5:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  $object->name->age makes no sense. Are you fetching the age of the name? If you want that format then name needs to be an object with a __toString() function that returns the name if it is cast as a string. The name-object would also need to have an age-property. A more sensible structure would be to have $obj->name and then $obj->age.
  
  – Magnus Eriksson
  Mar 8 at 5:53
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Define a magic __get method on your classes. See php.net/manual/language.oop5.overloading.php#object.get and more generally php.net/manual/language.oop5.magic.php
  
  – Phil
  Mar 8 at 5:56
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Nah, if you have $object->name->dave, then you are seriously doing OO wrong …
  
  – 04FS
  Mar 8 at 8:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @04FS That's what I'm getting from API to my request.
  
  – Rostyslav
  Mar 8 at 8:36
  

  
  
  
  

add a comment | 

0

So let's say I want to display name inside object, That would be

echo $object->name

If I want to display age of specific person, that would be

echo $object->name->dave->age

And I can display a lot of things.

However, What should I do if I don't know parameters which to display?

So let's say dave passed to me, and right now in $person

That would be something like

echo $object->name->$person->age

However I can't do that.

Is there any way to do that?

php

share|improve this question

edited Mar 8 at 7:58

Rostyslav

asked Mar 8 at 5:47

RostyslavRostyslav

366

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Need more detail, your question is not clear.
  
  – Ankur Tiwari
  Mar 8 at 5:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  $object->name->age makes no sense. Are you fetching the age of the name? If you want that format then name needs to be an object with a __toString() function that returns the name if it is cast as a string. The name-object would also need to have an age-property. A more sensible structure would be to have $obj->name and then $obj->age.
  
  – Magnus Eriksson
  Mar 8 at 5:53
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Define a magic __get method on your classes. See php.net/manual/language.oop5.overloading.php#object.get and more generally php.net/manual/language.oop5.magic.php
  
  – Phil
  Mar 8 at 5:56
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Nah, if you have $object->name->dave, then you are seriously doing OO wrong …
  
  – 04FS
  Mar 8 at 8:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @04FS That's what I'm getting from API to my request.
  
  – Rostyslav
  Mar 8 at 8:36
  

  
  
  
  

add a comment | 

So let's say I want to display name inside object, That would be

echo $object->name

If I want to display age of specific person, that would be

echo $object->name->dave->age

And I can display a lot of things.

However, What should I do if I don't know parameters which to display?

So let's say dave passed to me, and right now in $person

That would be something like

echo $object->name->$person->age

However I can't do that.

Is there any way to do that?

php

share|improve this question

edited Mar 8 at 7:58

Rostyslav

asked Mar 8 at 5:47

RostyslavRostyslav

366

echo $object->name

echo $object->name->dave->age

echo $object->name->$person->age

share|improve this question

edited Mar 8 at 7:58

Rostyslav

asked Mar 8 at 5:47

RostyslavRostyslav

366

share|improve this question

edited Mar 8 at 7:58

Rostyslav

asked Mar 8 at 5:47

RostyslavRostyslav

366

asked Mar 8 at 5:47

RostyslavRostyslav

366

asked Mar 8 at 5:47

RostyslavRostyslav

366

1 Answer
1

active

oldest

votes

-1

You can loop through object like this,

foreach ($object as $key => $value) 
 echo "$key => $valuen";

Also you can check if the variable is object or not using ,

is_object($object);

is_object()

share|improve this answer

answered Mar 8 at 5:56

Shoyeb SheikhShoyeb Sheikh

607211

add a comment | 

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-1

You can loop through object like this,

foreach ($object as $key => $value) 
 echo "$key => $valuen";

Also you can check if the variable is object or not using ,

is_object($object);

is_object()

share|improve this answer

answered Mar 8 at 5:56

Shoyeb SheikhShoyeb Sheikh

607211

add a comment | 

-1

You can loop through object like this,

foreach ($object as $key => $value) 
 echo "$key => $valuen";

Also you can check if the variable is object or not using ,

is_object($object);

is_object()

share|improve this answer

answered Mar 8 at 5:56

Shoyeb SheikhShoyeb Sheikh

607211

add a comment | 

You can loop through object like this,

foreach ($object as $key => $value) 
 echo "$key => $valuen";

Also you can check if the variable is object or not using ,

is_object($object);

is_object()

share|improve this answer

answered Mar 8 at 5:56

Shoyeb SheikhShoyeb Sheikh

607211

foreach ($object as $key => $value) 
 echo "$key => $valuen";

is_object($object);

share|improve this answer

answered Mar 8 at 5:56

Shoyeb SheikhShoyeb Sheikh

607211

answered Mar 8 at 5:56

Shoyeb SheikhShoyeb Sheikh

607211

answered Mar 8 at 5:56

Shoyeb SheikhShoyeb Sheikh

607211