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Append/prepend data to CSV column
2019 Community Moderator ElectionDifference between append vs. extend list methods in PythonHow to append something to an array?How do you append to a file in Python?What's the idiomatic syntax for prepending to a short python list?.append(), prepend(), .after() and .before()Maximum size of csv file that can be processed using Import-CsvMove-item inside loop (one liner)convert csv to tsv using Powershell; Import-Csv failsExtract Data from .txt files and export it to a .csv file #powershellThe property 'Name' cannot be found on this object. Verify that the property exists
I have spent over a week researching this question and none of the helps have worked. I started with this:
$File = "C:FOLDERindex - Copy.csv"
Import-Csv -Delim ',' $File |
ForEach-Object $_.col1 = "C:FOLDER$($_.col1)"; $_ |
Export-Csv Index2.csv -Delim ',' -NoTypeInformation
which I found elsewhere on this site and modified as I would expect. But I received this error:
Exception setting "col1": "The property 'col1' cannot be found on this object.
Verify that the property exists and can be set."
At line:2 char:69
+ Import-Csv -Delim ',' $File | ForEach-Object {$_.col1 = "C:FOLDER$($_.col1)";$_ ...
+ ~~~~~~~
+ CategoryInfo : NotSpecified: (:) [], SetValueInvocationException
+ FullyQualifiedErrorId : ExceptionWhenSetting
All I want to do is take a CSV file that looks like this:
Path,Filename
123456789,654321
234567891,543216
345678912,432165
and ultimately end with this:
Path,Filename
C:FOLDER123456789.jpg,654321.jpg
C:FOLDER234567891.jpg,543216.jpg
C:FOLDER345678912.jpg,432165.jpg
powershell append prepend
edited Mar 6 at 23:40
Ansgar Wiechers
145k13132190
asked Mar 6 at 22:01
CaptainJackCaptainJack
1
add a comment |
I have spent over a week researching this question and none of the helps have worked. I started with this:
$File = "C:FOLDERindex - Copy.csv"
Import-Csv -Delim ',' $File |
ForEach-Object $_.col1 = "C:FOLDER$($_.col1)"; $_ |
Export-Csv Index2.csv -Delim ',' -NoTypeInformation
which I found elsewhere on this site and modified as I would expect. But I received this error:
Exception setting "col1": "The property 'col1' cannot be found on this object.
Verify that the property exists and can be set."
At line:2 char:69
+ Import-Csv -Delim ',' $File | ForEach-Object {$_.col1 = "C:FOLDER$($_.col1)";$_ ...
+ ~~~~~~~
+ CategoryInfo : NotSpecified: (:) [], SetValueInvocationException
+ FullyQualifiedErrorId : ExceptionWhenSetting
All I want to do is take a CSV file that looks like this:
Path,Filename
123456789,654321
234567891,543216
345678912,432165
and ultimately end with this:
Path,Filename
C:FOLDER123456789.jpg,654321.jpg
C:FOLDER234567891.jpg,543216.jpg
C:FOLDER345678912.jpg,432165.jpg
powershell append prepend
edited Mar 6 at 23:40
Ansgar Wiechers
145k13132190
asked Mar 6 at 22:01
CaptainJackCaptainJack
1
What is not clear about the error? Your CSV does not have a column named "col1". Use the actual column name(s) instead.
– Ansgar Wiechers
Mar 6 at 23:36
D'OH! I've been looking at this for so long that I just needed a different pair of eyes. Thank you.
– CaptainJack
Mar 7 at 16:19
add a comment |
I have spent over a week researching this question and none of the helps have worked. I started with this:
$File = "C:FOLDERindex - Copy.csv"
Import-Csv -Delim ',' $File |
ForEach-Object $_.col1 = "C:FOLDER$($_.col1)"; $_ |
Export-Csv Index2.csv -Delim ',' -NoTypeInformation
which I found elsewhere on this site and modified as I would expect. But I received this error:
Exception setting "col1": "The property 'col1' cannot be found on this object.
Verify that the property exists and can be set."
At line:2 char:69
+ Import-Csv -Delim ',' $File | ForEach-Object {$_.col1 = "C:FOLDER$($_.col1)";$_ ...
+ ~~~~~~~
+ CategoryInfo : NotSpecified: (:) [], SetValueInvocationException
+ FullyQualifiedErrorId : ExceptionWhenSetting
All I want to do is take a CSV file that looks like this:
Path,Filename
123456789,654321
234567891,543216
345678912,432165
and ultimately end with this:
Path,Filename
C:FOLDER123456789.jpg,654321.jpg
C:FOLDER234567891.jpg,543216.jpg
C:FOLDER345678912.jpg,432165.jpg
powershell append prepend
edited Mar 6 at 23:40
Ansgar Wiechers
145k13132190
asked Mar 6 at 22:01
CaptainJackCaptainJack
1
I have spent over a week researching this question and none of the helps have worked. I started with this:
$File = "C:FOLDERindex - Copy.csv"
Import-Csv -Delim ',' $File |
ForEach-Object $_.col1 = "C:FOLDER$($_.col1)"; $_ |
Export-Csv Index2.csv -Delim ',' -NoTypeInformation
which I found elsewhere on this site and modified as I would expect. But I received this error:
Exception setting "col1": "The property 'col1' cannot be found on this object.
Verify that the property exists and can be set."
At line:2 char:69
+ Import-Csv -Delim ',' $File | ForEach-Object {$_.col1 = "C:FOLDER$($_.col1)";$_ ...
+ ~~~~~~~
+ CategoryInfo : NotSpecified: (:) [], SetValueInvocationException
+ FullyQualifiedErrorId : ExceptionWhenSetting
All I want to do is take a CSV file that looks like this:
Path,Filename
123456789,654321
234567891,543216
345678912,432165
and ultimately end with this:
Path,Filename
C:FOLDER123456789.jpg,654321.jpg
C:FOLDER234567891.jpg,543216.jpg
C:FOLDER345678912.jpg,432165.jpg
powershell append prepend
powershell append prepend
edited Mar 6 at 23:40
Ansgar Wiechers
145k13132190
asked Mar 6 at 22:01
CaptainJackCaptainJack
1
edited Mar 6 at 23:40
Ansgar Wiechers
145k13132190
asked Mar 6 at 22:01
CaptainJackCaptainJack
1
edited Mar 6 at 23:40
Ansgar Wiechers
145k13132190
edited Mar 6 at 23:40
Ansgar Wiechers
145k13132190
edited Mar 6 at 23:40
Ansgar Wiechers
145k13132190
145k13132190
asked Mar 6 at 22:01
CaptainJackCaptainJack
1
asked Mar 6 at 22:01
CaptainJackCaptainJack
1
asked Mar 6 at 22:01
CaptainJackCaptainJack
1
1
What is not clear about the error? Your CSV does not have a column named "col1". Use the actual column name(s) instead.
– Ansgar Wiechers
Mar 6 at 23:36
D'OH! I've been looking at this for so long that I just needed a different pair of eyes. Thank you.
– CaptainJack
Mar 7 at 16:19
add a comment |
What is not clear about the error? Your CSV does not have a column named "col1". Use the actual column name(s) instead.
– Ansgar Wiechers
Mar 6 at 23:36
D'OH! I've been looking at this for so long that I just needed a different pair of eyes. Thank you.
– CaptainJack
Mar 7 at 16:19
What is not clear about the error? Your CSV does not have a column named "col1". Use the actual column name(s) instead.
– Ansgar Wiechers
Mar 6 at 23:36
What is not clear about the error? Your CSV does not have a column named "col1". Use the actual column name(s) instead.
– Ansgar Wiechers
Mar 6 at 23:36
D'OH! I've been looking at this for so long that I just needed a different pair of eyes. Thank you.
– CaptainJack
Mar 7 at 16:19
D'OH! I've been looking at this for so long that I just needed a different pair of eyes. Thank you.
– CaptainJack
Mar 7 at 16:19
add a comment |
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What is not clear about the error? Your CSV does not have a column named "col1". Use the actual column name(s) instead.
– Ansgar Wiechers
Mar 6 at 23:36
D'OH! I've been looking at this for so long that I just needed a different pair of eyes. Thank you.
– CaptainJack
Mar 7 at 16:19