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Django's ListView - How to customise it
2019 Community Moderator Electiondjango count of foreign key modelHow to merge two dictionaries in a single expression?How do I check if a list is empty?How do I check whether a file exists without exceptions?How can I safely create a nested directory in Python?How do I sort a dictionary by value?How do I list all files of a directory?Show information of subclass in list_display djangoHow to expose some specific fields of model_b based on a field of model_a?How to define Mode with generic ForeignKey in DjangoHow to create an incremental id for a set of projects per user in Django?
I am sorry if this is a duplicate, but I did not find any answer to my question.
My issue below
I am really struggling to understand how to customise my views when using ListView. I read the Django documentation, but I find it very brief.
What I would like to do is to count the questions for each topic and return the topic with the most questions. I would be able to count the number of questions for each topic with the following line of code in my models.py (Topic class):
def questions_count(self):
return Question.objects.filter(question__topic = self).count()
However, I would like to return only the most popular Topic and the number of questions.
Using a function-based view, I would loop over the topics, and I would create two variables storing the topic name and the number of questions. However, with the ListView I do not know whether to use get_context_data(), get_queryset() or something else.
My view class:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
My models:
class Topic(models.Model):
name = models.CharField(max_length=30, unique=True)
description = models.CharField(max_length=100)
class Question(models.Model):
....
topic = models.ForeignKey(Topic, related_name='questions', on_delete=models.CASCADE)
....
python django django-models django-views django-generic-views
add a comment |
I am sorry if this is a duplicate, but I did not find any answer to my question.
My issue below
I am really struggling to understand how to customise my views when using ListView. I read the Django documentation, but I find it very brief.
What I would like to do is to count the questions for each topic and return the topic with the most questions. I would be able to count the number of questions for each topic with the following line of code in my models.py (Topic class):
def questions_count(self):
return Question.objects.filter(question__topic = self).count()
However, I would like to return only the most popular Topic and the number of questions.
Using a function-based view, I would loop over the topics, and I would create two variables storing the topic name and the number of questions. However, with the ListView I do not know whether to use get_context_data(), get_queryset() or something else.
My view class:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
My models:
class Topic(models.Model):
name = models.CharField(max_length=30, unique=True)
description = models.CharField(max_length=100)
class Question(models.Model):
....
topic = models.ForeignKey(Topic, related_name='questions', on_delete=models.CASCADE)
....
python django django-models django-views django-generic-views
add a comment |
I am sorry if this is a duplicate, but I did not find any answer to my question.
My issue below
I am really struggling to understand how to customise my views when using ListView. I read the Django documentation, but I find it very brief.
What I would like to do is to count the questions for each topic and return the topic with the most questions. I would be able to count the number of questions for each topic with the following line of code in my models.py (Topic class):
def questions_count(self):
return Question.objects.filter(question__topic = self).count()
However, I would like to return only the most popular Topic and the number of questions.
Using a function-based view, I would loop over the topics, and I would create two variables storing the topic name and the number of questions. However, with the ListView I do not know whether to use get_context_data(), get_queryset() or something else.
My view class:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
My models:
class Topic(models.Model):
name = models.CharField(max_length=30, unique=True)
description = models.CharField(max_length=100)
class Question(models.Model):
....
topic = models.ForeignKey(Topic, related_name='questions', on_delete=models.CASCADE)
....
python django django-models django-views django-generic-views
I am sorry if this is a duplicate, but I did not find any answer to my question.
My issue below
I am really struggling to understand how to customise my views when using ListView. I read the Django documentation, but I find it very brief.
What I would like to do is to count the questions for each topic and return the topic with the most questions. I would be able to count the number of questions for each topic with the following line of code in my models.py (Topic class):
def questions_count(self):
return Question.objects.filter(question__topic = self).count()
However, I would like to return only the most popular Topic and the number of questions.
Using a function-based view, I would loop over the topics, and I would create two variables storing the topic name and the number of questions. However, with the ListView I do not know whether to use get_context_data(), get_queryset() or something else.
My view class:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
My models:
class Topic(models.Model):
name = models.CharField(max_length=30, unique=True)
description = models.CharField(max_length=100)
class Question(models.Model):
....
topic = models.ForeignKey(Topic, related_name='questions', on_delete=models.CASCADE)
....
python django django-models django-views django-generic-views
python django django-models django-views django-generic-views
asked Mar 6 at 22:08
cpitcpit
237
237
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You might want to try using .annotate()
to get the count of Questions
associated with each Topic
:
from django.db.models import Count
topics_count = Topics.objects.annotate(count_of_questions=Count('question'))
Each Topic
object will have a new attribute count_of_questions
which is the total number of questions associated with each Topic
.
In your ListView
:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
def get_queryset(self):
queryset = super(TopicsView, self).get_queryset()
queryset = queryset.annotate(count_of_questions=Count('question'))
Then you should be able to use dictsortreversed to do the following in your template, which should return the topic with the most questions first:
% for t in topics
t.count_of_questions
% endfor %
There's a similar question and answer in the following SO Q&A
Thank you for your question. However, I am looking to return only the Topic instance with the most questions. I do not want to return a queryset.
– cpit
Mar 7 at 11:03
I'm a little confused by your comment -- if you want to use Django'sListView
this is the most efficient method. In your solution you are adding toget_context_data()
and I am adding toget_queryset()
-- no real difference there. To only show theTopic
with the most questions, just limit the results in your template to the first record? It might help if you explain what you trying to accomplish with getting the count of questions in a variable (like an if/else statement or something)?
– tatlar
Mar 11 at 16:33
add a comment |
In the end, I have managed to do it through the get_context_data() function. This is how my solution looks like:
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
mostQuestions = context['object_list'][0].questions_count()
mostQuestionsTopic = context['object_list'][0]
for topic in context['object_list']:
if topic.questions_count() > mostQuestions:
mostQuestions = topic.questions_count()
mostQuestionsTopic = topic
context['mostQuestions'] = mostQuestions
context['mostQuestionsTopic'] = mostQuestionsTopic
return context
Is there a more efficient solution?
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You might want to try using .annotate()
to get the count of Questions
associated with each Topic
:
from django.db.models import Count
topics_count = Topics.objects.annotate(count_of_questions=Count('question'))
Each Topic
object will have a new attribute count_of_questions
which is the total number of questions associated with each Topic
.
In your ListView
:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
def get_queryset(self):
queryset = super(TopicsView, self).get_queryset()
queryset = queryset.annotate(count_of_questions=Count('question'))
Then you should be able to use dictsortreversed to do the following in your template, which should return the topic with the most questions first:
% for t in topics
t.count_of_questions
% endfor %
There's a similar question and answer in the following SO Q&A
Thank you for your question. However, I am looking to return only the Topic instance with the most questions. I do not want to return a queryset.
– cpit
Mar 7 at 11:03
I'm a little confused by your comment -- if you want to use Django'sListView
this is the most efficient method. In your solution you are adding toget_context_data()
and I am adding toget_queryset()
-- no real difference there. To only show theTopic
with the most questions, just limit the results in your template to the first record? It might help if you explain what you trying to accomplish with getting the count of questions in a variable (like an if/else statement or something)?
– tatlar
Mar 11 at 16:33
add a comment |
You might want to try using .annotate()
to get the count of Questions
associated with each Topic
:
from django.db.models import Count
topics_count = Topics.objects.annotate(count_of_questions=Count('question'))
Each Topic
object will have a new attribute count_of_questions
which is the total number of questions associated with each Topic
.
In your ListView
:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
def get_queryset(self):
queryset = super(TopicsView, self).get_queryset()
queryset = queryset.annotate(count_of_questions=Count('question'))
Then you should be able to use dictsortreversed to do the following in your template, which should return the topic with the most questions first:
% for t in topics
t.count_of_questions
% endfor %
There's a similar question and answer in the following SO Q&A
Thank you for your question. However, I am looking to return only the Topic instance with the most questions. I do not want to return a queryset.
– cpit
Mar 7 at 11:03
I'm a little confused by your comment -- if you want to use Django'sListView
this is the most efficient method. In your solution you are adding toget_context_data()
and I am adding toget_queryset()
-- no real difference there. To only show theTopic
with the most questions, just limit the results in your template to the first record? It might help if you explain what you trying to accomplish with getting the count of questions in a variable (like an if/else statement or something)?
– tatlar
Mar 11 at 16:33
add a comment |
You might want to try using .annotate()
to get the count of Questions
associated with each Topic
:
from django.db.models import Count
topics_count = Topics.objects.annotate(count_of_questions=Count('question'))
Each Topic
object will have a new attribute count_of_questions
which is the total number of questions associated with each Topic
.
In your ListView
:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
def get_queryset(self):
queryset = super(TopicsView, self).get_queryset()
queryset = queryset.annotate(count_of_questions=Count('question'))
Then you should be able to use dictsortreversed to do the following in your template, which should return the topic with the most questions first:
% for t in topics
t.count_of_questions
% endfor %
There's a similar question and answer in the following SO Q&A
You might want to try using .annotate()
to get the count of Questions
associated with each Topic
:
from django.db.models import Count
topics_count = Topics.objects.annotate(count_of_questions=Count('question'))
Each Topic
object will have a new attribute count_of_questions
which is the total number of questions associated with each Topic
.
In your ListView
:
class TopicsView(ListView):
model = Topic
context_object_name = 'topics'
template_name = 'home.html'
def get_queryset(self):
queryset = super(TopicsView, self).get_queryset()
queryset = queryset.annotate(count_of_questions=Count('question'))
Then you should be able to use dictsortreversed to do the following in your template, which should return the topic with the most questions first:
% for t in topics
t.count_of_questions
% endfor %
There's a similar question and answer in the following SO Q&A
answered Mar 6 at 22:57
tatlartatlar
1,69822029
1,69822029
Thank you for your question. However, I am looking to return only the Topic instance with the most questions. I do not want to return a queryset.
– cpit
Mar 7 at 11:03
I'm a little confused by your comment -- if you want to use Django'sListView
this is the most efficient method. In your solution you are adding toget_context_data()
and I am adding toget_queryset()
-- no real difference there. To only show theTopic
with the most questions, just limit the results in your template to the first record? It might help if you explain what you trying to accomplish with getting the count of questions in a variable (like an if/else statement or something)?
– tatlar
Mar 11 at 16:33
add a comment |
Thank you for your question. However, I am looking to return only the Topic instance with the most questions. I do not want to return a queryset.
– cpit
Mar 7 at 11:03
I'm a little confused by your comment -- if you want to use Django'sListView
this is the most efficient method. In your solution you are adding toget_context_data()
and I am adding toget_queryset()
-- no real difference there. To only show theTopic
with the most questions, just limit the results in your template to the first record? It might help if you explain what you trying to accomplish with getting the count of questions in a variable (like an if/else statement or something)?
– tatlar
Mar 11 at 16:33
Thank you for your question. However, I am looking to return only the Topic instance with the most questions. I do not want to return a queryset.
– cpit
Mar 7 at 11:03
Thank you for your question. However, I am looking to return only the Topic instance with the most questions. I do not want to return a queryset.
– cpit
Mar 7 at 11:03
I'm a little confused by your comment -- if you want to use Django's
ListView
this is the most efficient method. In your solution you are adding to get_context_data()
and I am adding to get_queryset()
-- no real difference there. To only show the Topic
with the most questions, just limit the results in your template to the first record? It might help if you explain what you trying to accomplish with getting the count of questions in a variable (like an if/else statement or something)?– tatlar
Mar 11 at 16:33
I'm a little confused by your comment -- if you want to use Django's
ListView
this is the most efficient method. In your solution you are adding to get_context_data()
and I am adding to get_queryset()
-- no real difference there. To only show the Topic
with the most questions, just limit the results in your template to the first record? It might help if you explain what you trying to accomplish with getting the count of questions in a variable (like an if/else statement or something)?– tatlar
Mar 11 at 16:33
add a comment |
In the end, I have managed to do it through the get_context_data() function. This is how my solution looks like:
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
mostQuestions = context['object_list'][0].questions_count()
mostQuestionsTopic = context['object_list'][0]
for topic in context['object_list']:
if topic.questions_count() > mostQuestions:
mostQuestions = topic.questions_count()
mostQuestionsTopic = topic
context['mostQuestions'] = mostQuestions
context['mostQuestionsTopic'] = mostQuestionsTopic
return context
Is there a more efficient solution?
add a comment |
In the end, I have managed to do it through the get_context_data() function. This is how my solution looks like:
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
mostQuestions = context['object_list'][0].questions_count()
mostQuestionsTopic = context['object_list'][0]
for topic in context['object_list']:
if topic.questions_count() > mostQuestions:
mostQuestions = topic.questions_count()
mostQuestionsTopic = topic
context['mostQuestions'] = mostQuestions
context['mostQuestionsTopic'] = mostQuestionsTopic
return context
Is there a more efficient solution?
add a comment |
In the end, I have managed to do it through the get_context_data() function. This is how my solution looks like:
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
mostQuestions = context['object_list'][0].questions_count()
mostQuestionsTopic = context['object_list'][0]
for topic in context['object_list']:
if topic.questions_count() > mostQuestions:
mostQuestions = topic.questions_count()
mostQuestionsTopic = topic
context['mostQuestions'] = mostQuestions
context['mostQuestionsTopic'] = mostQuestionsTopic
return context
Is there a more efficient solution?
In the end, I have managed to do it through the get_context_data() function. This is how my solution looks like:
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
mostQuestions = context['object_list'][0].questions_count()
mostQuestionsTopic = context['object_list'][0]
for topic in context['object_list']:
if topic.questions_count() > mostQuestions:
mostQuestions = topic.questions_count()
mostQuestionsTopic = topic
context['mostQuestions'] = mostQuestions
context['mostQuestionsTopic'] = mostQuestionsTopic
return context
Is there a more efficient solution?
answered Mar 7 at 14:03
cpitcpit
237
237
add a comment |
add a comment |
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