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Output HTTP status codes via popup



2019 Community Moderator ElectionHow do I get the path of the assembly the code is in?“The Controls collection cannot be modified because the control contains code blocks”Getting Http Status code number (200, 301, 404, etc.) from HttpWebRequest and HttpWebResponseThe provided URI scheme 'https' is invalid; expected 'http'. Parameter name: viaSystem.Net.WebException HTTP status codeHow to make HTTP POST web requestTry-catch speeding up my code?Writing to output window of Visual Studio?Returning http status code from Web Api controllerWhat C# AES encryption options to use so result can be decrypted on a public web site?










1















I am trying to output a small popup-like window to the user saying either the restful command was successfully accepted or not (and display the Http Code).



I am really looking for direction on how to do this properly in ASP.NET MVC.



Controller Function



 public void ExportJira()


string postUrl = "https://somewebsite.org/rest/api/2/issue";
var httpWebRequest = (HttpWebRequest)WebRequest.Create(postUrl);
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "POST";
//Using Service Account for Demo Jira Instance
httpWebRequest.Headers["Authorization"] = "Basic " + Convert.ToBase64String(Encoding.Default.GetBytes("FakeAccount:fakePw"));

using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))

string json = @"""fields"":""project"":""key"": ""SDR"",""summary"": ""This is SDR Web App"",""issuetype"" : ""id"":""3""";

streamWriter.Write(json);
streamWriter.Flush();
streamWriter.Close();
HttpWebResponse httpResponse = null;
try

httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))

var result = streamReader.ReadToEnd();
System.Diagnostics.Debug.WriteLine("Errorcode: 0", (int)httpResponse.StatusCode);
System.Diagnostics.Debug.WriteLine("Support Headers: n" + httpResponse.SupportsHeaders + "n");
System.Diagnostics.Debug.WriteLine("Headers: n" + httpResponse.Headers + "n");
TempData["msg"] = "<script>alert('Success!" + (int)httpResponse.StatusCode + "');</script>";


catch (WebException e)

if (e.Status == WebExceptionStatus.ProtocolError)

httpResponse = (HttpWebResponse)e.Response;
TempData["msg"] = "<script>alert('Failed!" + (int)httpResponse.StatusCode + "');</script>";

else

TempData["msg"] = "<script>alert('Failed!" + (int)httpResponse.StatusCode + "');</script>";


finally

if (httpResponse != null)

httpResponse.Close();







View Code



 @Html.ActionLink("Export to Jira", "ExportJira", null, new id = "myLink" )
@Html.Raw(TempData["msg"])









share|improve this question


























    1















    I am trying to output a small popup-like window to the user saying either the restful command was successfully accepted or not (and display the Http Code).



    I am really looking for direction on how to do this properly in ASP.NET MVC.



    Controller Function



     public void ExportJira()


    string postUrl = "https://somewebsite.org/rest/api/2/issue";
    var httpWebRequest = (HttpWebRequest)WebRequest.Create(postUrl);
    httpWebRequest.ContentType = "application/json";
    httpWebRequest.Method = "POST";
    //Using Service Account for Demo Jira Instance
    httpWebRequest.Headers["Authorization"] = "Basic " + Convert.ToBase64String(Encoding.Default.GetBytes("FakeAccount:fakePw"));

    using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))

    string json = @"""fields"":""project"":""key"": ""SDR"",""summary"": ""This is SDR Web App"",""issuetype"" : ""id"":""3""";

    streamWriter.Write(json);
    streamWriter.Flush();
    streamWriter.Close();
    HttpWebResponse httpResponse = null;
    try

    httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
    using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))

    var result = streamReader.ReadToEnd();
    System.Diagnostics.Debug.WriteLine("Errorcode: 0", (int)httpResponse.StatusCode);
    System.Diagnostics.Debug.WriteLine("Support Headers: n" + httpResponse.SupportsHeaders + "n");
    System.Diagnostics.Debug.WriteLine("Headers: n" + httpResponse.Headers + "n");
    TempData["msg"] = "<script>alert('Success!" + (int)httpResponse.StatusCode + "');</script>";


    catch (WebException e)

    if (e.Status == WebExceptionStatus.ProtocolError)

    httpResponse = (HttpWebResponse)e.Response;
    TempData["msg"] = "<script>alert('Failed!" + (int)httpResponse.StatusCode + "');</script>";

    else

    TempData["msg"] = "<script>alert('Failed!" + (int)httpResponse.StatusCode + "');</script>";


    finally

    if (httpResponse != null)

    httpResponse.Close();







    View Code



     @Html.ActionLink("Export to Jira", "ExportJira", null, new id = "myLink" )
    @Html.Raw(TempData["msg"])









    share|improve this question
























      1












      1








      1








      I am trying to output a small popup-like window to the user saying either the restful command was successfully accepted or not (and display the Http Code).



      I am really looking for direction on how to do this properly in ASP.NET MVC.



      Controller Function



       public void ExportJira()


      string postUrl = "https://somewebsite.org/rest/api/2/issue";
      var httpWebRequest = (HttpWebRequest)WebRequest.Create(postUrl);
      httpWebRequest.ContentType = "application/json";
      httpWebRequest.Method = "POST";
      //Using Service Account for Demo Jira Instance
      httpWebRequest.Headers["Authorization"] = "Basic " + Convert.ToBase64String(Encoding.Default.GetBytes("FakeAccount:fakePw"));

      using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))

      string json = @"""fields"":""project"":""key"": ""SDR"",""summary"": ""This is SDR Web App"",""issuetype"" : ""id"":""3""";

      streamWriter.Write(json);
      streamWriter.Flush();
      streamWriter.Close();
      HttpWebResponse httpResponse = null;
      try

      httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
      using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))

      var result = streamReader.ReadToEnd();
      System.Diagnostics.Debug.WriteLine("Errorcode: 0", (int)httpResponse.StatusCode);
      System.Diagnostics.Debug.WriteLine("Support Headers: n" + httpResponse.SupportsHeaders + "n");
      System.Diagnostics.Debug.WriteLine("Headers: n" + httpResponse.Headers + "n");
      TempData["msg"] = "<script>alert('Success!" + (int)httpResponse.StatusCode + "');</script>";


      catch (WebException e)

      if (e.Status == WebExceptionStatus.ProtocolError)

      httpResponse = (HttpWebResponse)e.Response;
      TempData["msg"] = "<script>alert('Failed!" + (int)httpResponse.StatusCode + "');</script>";

      else

      TempData["msg"] = "<script>alert('Failed!" + (int)httpResponse.StatusCode + "');</script>";


      finally

      if (httpResponse != null)

      httpResponse.Close();







      View Code



       @Html.ActionLink("Export to Jira", "ExportJira", null, new id = "myLink" )
      @Html.Raw(TempData["msg"])









      share|improve this question














      I am trying to output a small popup-like window to the user saying either the restful command was successfully accepted or not (and display the Http Code).



      I am really looking for direction on how to do this properly in ASP.NET MVC.



      Controller Function



       public void ExportJira()


      string postUrl = "https://somewebsite.org/rest/api/2/issue";
      var httpWebRequest = (HttpWebRequest)WebRequest.Create(postUrl);
      httpWebRequest.ContentType = "application/json";
      httpWebRequest.Method = "POST";
      //Using Service Account for Demo Jira Instance
      httpWebRequest.Headers["Authorization"] = "Basic " + Convert.ToBase64String(Encoding.Default.GetBytes("FakeAccount:fakePw"));

      using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))

      string json = @"""fields"":""project"":""key"": ""SDR"",""summary"": ""This is SDR Web App"",""issuetype"" : ""id"":""3""";

      streamWriter.Write(json);
      streamWriter.Flush();
      streamWriter.Close();
      HttpWebResponse httpResponse = null;
      try

      httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
      using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))

      var result = streamReader.ReadToEnd();
      System.Diagnostics.Debug.WriteLine("Errorcode: 0", (int)httpResponse.StatusCode);
      System.Diagnostics.Debug.WriteLine("Support Headers: n" + httpResponse.SupportsHeaders + "n");
      System.Diagnostics.Debug.WriteLine("Headers: n" + httpResponse.Headers + "n");
      TempData["msg"] = "<script>alert('Success!" + (int)httpResponse.StatusCode + "');</script>";


      catch (WebException e)

      if (e.Status == WebExceptionStatus.ProtocolError)

      httpResponse = (HttpWebResponse)e.Response;
      TempData["msg"] = "<script>alert('Failed!" + (int)httpResponse.StatusCode + "');</script>";

      else

      TempData["msg"] = "<script>alert('Failed!" + (int)httpResponse.StatusCode + "');</script>";


      finally

      if (httpResponse != null)

      httpResponse.Close();







      View Code



       @Html.ActionLink("Export to Jira", "ExportJira", null, new id = "myLink" )
      @Html.Raw(TempData["msg"])






      c# asp.net asp.net-mvc-4






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 6 at 21:10









      Robert GilRobert Gil

      61




      61






















          1 Answer
          1






          active

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          0














          Every get or post controller function should return a view model, that can be used by the view to display whatever is relevant. Rather than using TempData, do something like this



          class ExportJiraViewModel

          public string Message get;set;


          public IActionResult ExportJira()

          var vm = new ExportJiraViewModel();

          // fill out vm where appropriate

          return View(vm);






          share|improve this answer






















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            1 Answer
            1






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            oldest

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            active

            oldest

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            active

            oldest

            votes









            0














            Every get or post controller function should return a view model, that can be used by the view to display whatever is relevant. Rather than using TempData, do something like this



            class ExportJiraViewModel

            public string Message get;set;


            public IActionResult ExportJira()

            var vm = new ExportJiraViewModel();

            // fill out vm where appropriate

            return View(vm);






            share|improve this answer



























              0














              Every get or post controller function should return a view model, that can be used by the view to display whatever is relevant. Rather than using TempData, do something like this



              class ExportJiraViewModel

              public string Message get;set;


              public IActionResult ExportJira()

              var vm = new ExportJiraViewModel();

              // fill out vm where appropriate

              return View(vm);






              share|improve this answer

























                0












                0








                0







                Every get or post controller function should return a view model, that can be used by the view to display whatever is relevant. Rather than using TempData, do something like this



                class ExportJiraViewModel

                public string Message get;set;


                public IActionResult ExportJira()

                var vm = new ExportJiraViewModel();

                // fill out vm where appropriate

                return View(vm);






                share|improve this answer













                Every get or post controller function should return a view model, that can be used by the view to display whatever is relevant. Rather than using TempData, do something like this



                class ExportJiraViewModel

                public string Message get;set;


                public IActionResult ExportJira()

                var vm = new ExportJiraViewModel();

                // fill out vm where appropriate

                return View(vm);







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 6 at 22:17









                NeilNeil

                5,01211638




                5,01211638





























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