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i have data “test1@gmail.com,test2@gmail.com” how to make the result look like this
Secure hash and salt for PHP passwordsReference — What does this symbol mean in PHP?How does PHP 'foreach' actually work?PHP Array inside ArrayHow to implode array with key and value without foreach in PHPReference - What does this error mean in PHP?Implode in Reverse Order in PHP with out using array_reverseAccessing an array in an objectHow to store a function result in an array for JSON encoding?Prepared String Before Comma
my code :
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
$to = implode(",",$newData);
echo json_encode($to)
result :
"test1@gmail.com, test2@gmail.com"
question : how to make the results look like this:
"test1@gmail.com", "test2@gmail.com"
php codeigniter
add a comment |
my code :
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
$to = implode(",",$newData);
echo json_encode($to)
result :
"test1@gmail.com, test2@gmail.com"
question : how to make the results look like this:
"test1@gmail.com", "test2@gmail.com"
php codeigniter
2
remove this$to = implode(",",$newData);
and change thisecho json_encode($newData)
~ results["test1@gmail.com", "test2@gmail.com"]
Sandbox And in JS it's an array not a string, so you have no parsing to do of it.data[0]
ordata[1]
etc.
– ArtisticPhoenix
Mar 7 at 1:43
In case you are not really asking for JSON, but actually want the result exactly as shown, the answer would be that you implode the array with the separator", "
, and output an additional"
before and after the whole thing …
– 04FS
Mar 7 at 8:37
add a comment |
my code :
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
$to = implode(",",$newData);
echo json_encode($to)
result :
"test1@gmail.com, test2@gmail.com"
question : how to make the results look like this:
"test1@gmail.com", "test2@gmail.com"
php codeigniter
my code :
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
$to = implode(",",$newData);
echo json_encode($to)
result :
"test1@gmail.com, test2@gmail.com"
question : how to make the results look like this:
"test1@gmail.com", "test2@gmail.com"
php codeigniter
php codeigniter
edited Mar 7 at 2:08
FluffyKitten
4,85742438
4,85742438
asked Mar 7 at 1:30
Anasrul YusufAnasrul Yusuf
141
141
2
remove this$to = implode(",",$newData);
and change thisecho json_encode($newData)
~ results["test1@gmail.com", "test2@gmail.com"]
Sandbox And in JS it's an array not a string, so you have no parsing to do of it.data[0]
ordata[1]
etc.
– ArtisticPhoenix
Mar 7 at 1:43
In case you are not really asking for JSON, but actually want the result exactly as shown, the answer would be that you implode the array with the separator", "
, and output an additional"
before and after the whole thing …
– 04FS
Mar 7 at 8:37
add a comment |
2
remove this$to = implode(",",$newData);
and change thisecho json_encode($newData)
~ results["test1@gmail.com", "test2@gmail.com"]
Sandbox And in JS it's an array not a string, so you have no parsing to do of it.data[0]
ordata[1]
etc.
– ArtisticPhoenix
Mar 7 at 1:43
In case you are not really asking for JSON, but actually want the result exactly as shown, the answer would be that you implode the array with the separator", "
, and output an additional"
before and after the whole thing …
– 04FS
Mar 7 at 8:37
2
2
remove this
$to = implode(",",$newData);
and change this echo json_encode($newData)
~ results ["test1@gmail.com", "test2@gmail.com"]
Sandbox And in JS it's an array not a string, so you have no parsing to do of it. data[0]
or data[1]
etc.– ArtisticPhoenix
Mar 7 at 1:43
remove this
$to = implode(",",$newData);
and change this echo json_encode($newData)
~ results ["test1@gmail.com", "test2@gmail.com"]
Sandbox And in JS it's an array not a string, so you have no parsing to do of it. data[0]
or data[1]
etc.– ArtisticPhoenix
Mar 7 at 1:43
In case you are not really asking for JSON, but actually want the result exactly as shown, the answer would be that you implode the array with the separator
", "
, and output an additional "
before and after the whole thing …– 04FS
Mar 7 at 8:37
In case you are not really asking for JSON, but actually want the result exactly as shown, the answer would be that you implode the array with the separator
", "
, and output an additional "
before and after the whole thing …– 04FS
Mar 7 at 8:37
add a comment |
1 Answer
1
active
oldest
votes
Just remove the implode() Function.The implode() is a builtin function in PHP and is used to join the elements of an array. The separator (,) parameter of implode() is recommended to always use two parameters for backwards compatibility.
<?php
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
echo json_encode($newData);
?>
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just remove the implode() Function.The implode() is a builtin function in PHP and is used to join the elements of an array. The separator (,) parameter of implode() is recommended to always use two parameters for backwards compatibility.
<?php
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
echo json_encode($newData);
?>
add a comment |
Just remove the implode() Function.The implode() is a builtin function in PHP and is used to join the elements of an array. The separator (,) parameter of implode() is recommended to always use two parameters for backwards compatibility.
<?php
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
echo json_encode($newData);
?>
add a comment |
Just remove the implode() Function.The implode() is a builtin function in PHP and is used to join the elements of an array. The separator (,) parameter of implode() is recommended to always use two parameters for backwards compatibility.
<?php
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
echo json_encode($newData);
?>
Just remove the implode() Function.The implode() is a builtin function in PHP and is used to join the elements of an array. The separator (,) parameter of implode() is recommended to always use two parameters for backwards compatibility.
<?php
$read = $this->m_crud->read_data("subscribe","*");
$newData=array();
foreach($read as $key)
$newData[] = $key["email"];
echo json_encode($newData);
?>
answered Mar 7 at 6:37
Makdia HussainMakdia Hussain
1764
1764
add a comment |
add a comment |
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2
remove this
$to = implode(",",$newData);
and change thisecho json_encode($newData)
~ results["test1@gmail.com", "test2@gmail.com"]
Sandbox And in JS it's an array not a string, so you have no parsing to do of it.data[0]
ordata[1]
etc.– ArtisticPhoenix
Mar 7 at 1:43
In case you are not really asking for JSON, but actually want the result exactly as shown, the answer would be that you implode the array with the separator
", "
, and output an additional"
before and after the whole thing …– 04FS
Mar 7 at 8:37